Question

我正在使用GitHub GraphQL API，需要过滤掉一些响应数据，但它是如此深层嵌套。下面是我正在处理的响应的剪切示例。

case "text":
    reader.next();
    if(reader != null && !"".equals(reader.toString()) && reader.hasText())                     
    writer1.println("Text: " + reader.getText());
    break;

我想要实现的是能够根据他们的登录过滤评论者。我怎样才能过滤掉节点中的一些地图以达到以下结果？

%{"name" => "repo",
  "pullRequests" => %{
    "nodes" => [%{
      "reviews" => %{
        "nodes" => [
          %{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"}
        ]
      }
    }]
  }
}

Answer 1

这是Bill_no的完美用例：

update_in

输出：

map = %{"name" => "repo",
  "pullRequests" => %{
    "nodes" => [%{
      "reviews" => %{
        "nodes" => [
          %{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"},
          %{"author" => %{"login" => "BAR"}, "state" => "COMMENTED"}
        ]
      }
    }]
  }
}

map2 = update_in(map, ["pullRequests", "nodes", Access.all(), "reviews", "nodes"], fn nodes ->
  for %{"author" => %{"login" => "FOO"}} = node <- nodes, do: node
end)

IO.inspect map2

%{"name" => "repo", "pullRequests" => %{"nodes" => [%{"reviews" => %{"nodes" => [%{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"}, %{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"}, %{"author" => %{"login" => "FOO"}, "state" => "COMMENTED"}]}}]}}让我们在进行更新时迭代列表的所有元素。这意味着如果您的顶级“节点”有多个项目，则所有项目都将根据我们的逻辑进行过滤。

^{注意：您的代码语法无效，所以我假设您打算将Access.all()包装在地图中。}

如何在列表中过滤深层嵌套的地图？

1 个答案: