Question

我有一个变量$ tinder-＆gt;建议。当我把它保存在var_dump中时。

与var_dump（$ tinder-＆gt;推荐）相似;

它给出了一个在下面的数组。

object(stdClass)#7 (2) {
  ["status"]=> int(200)
  ["results"]=> array(47) {
    [0]=> object(stdClass)#34 (23) {

      ["group_matched"]=> bool(false)
      ["distance_mi"]=> int(14)
      ["content_hash"]=> string(47) "5nVT6PhabtGrSRqiRiLAfqXH1LFkps25sagHawimxt5Eh4r"
      ["common_friends"]=> array(0) { } 

      ["common_likes"]=> array(0) { } 
      ["common_friend_count"]=> int(0) 
      ["common_like_count"]=> int(0) 
      ["connection_count"]=> int(0) 
      ["_id"]=> string(24) "583c9fd7298a09eb42f32df1" 
      ["bio"]=> string(353) "Family, friends, my pooches, music. Old fashioned as far as relationships go. I'm not an apple polisher. Not sure if this is the place to find a keeper, but who knows. I'd say this is better than meeting someone at a bar haha. Music: Blues, Soul, Doo Wop, Folk, Bluegrass, Country, Doom, Punk Red Heeler & Old English Bulldog 6'-0" for those who care" 
      ["birth_date"]=> string(24) "1989-11-23T20:12:56.493Z" 
      ["name"]=> string(5) "Trent" 
      ["ping_time"]=> string(24) "2014-12-09T00:00:00.000Z" 
      ["photos"]=> array(6) { 
        [0]=> object(stdClass)#33 (3) { 
          ["id"]=> string(36) "318ad35d-3e14-44c6-8348-3aacfc4594bd" 
          ["url"]=> string(92) "http://images.gotinder.com/583c9fd7298a09eb42f32df1/318ad35d-3e14-44c6-8348-3aacfc4594bd.jpg" ["processedFiles"]=> array(4) { 
            [0]=> object(stdClass)#35 (3) { 
              ["url"]=> string(100) "http://images.gotinder.com/583c9fd7298a09eb42f32df1/640x640_318ad35d-3e14-44c6-8348-3aacfc4594bd.jpg" 
              ["height"]=> int(640) 
              ["width"]=> int(640) }

            [1]=> object(stdClass)#36 (3) { 
              ["url"]=> string(100) "http://images.gotinder.com/583c9fd7298a09eb42f32df1/320x320_318ad35d-3e14-44c6-8348-3aacfc4594bd.jpg" 
              ["height"]=> int(320) 
              ["width"]=> int(320) }

            [2]=> object(stdClass)#37 (3) { 
              ["url"]=> string(100) "http://images.gotinder.com/583c9fd7298a09eb42f32df1/172x172_318ad35d-3e14-44c6-8348-3aacfc4594bd.jpg" 
              ["height"]=> int(172) 
              ["width"]=> int(172) }

现在我只想从＆＃39; _id＆＃39;中获得价值。＆安培; ＆＃39;名称＆＃39;并将它们保存在数据库中。我已经尝试了下面的代码，但它没有给出任何结果，所以你能帮助我，我怎样才能提取_id＆amp;的值命名并将其保存在数据库中？

   if ($tinder->recommendations() > 0) {
      foreach($tinder->recommendations() as $contact) {

          if( property_exists( $contact, '_id') &&
            property_exists( $contact, 'name')){

              echo "$contact->_id";

          } else {

              echo "property doesn't exists";

          }

      }
    } else {

      echo "object doesn't exists";

    }

结果：财产不存在。

if ($tinder->recommendations > 0) {
  foreach($tinder->recommendations as $contact) {

      if( property_exists( $contact, '_id') &&
        property_exists( $contact, 'name')){

          echo "$contact->_id";

      } else {

          echo "property doesn't exists";

      }

  }
} else {

  echo "object doesn't exists";

}

结果：对象不存在。

if ($tinder->recommendations->results > 0) {
  foreach($tinder->recommendations->results as $contact) {

      if( property_exists( $contact, '_id') &&
        property_exists( $contact, 'name')){

          echo "$contact->_id";

      } else {

          echo "property doesn't exists";

      }

  }
} else {

  echo "object doesn't exists";

}

结果：对象不存在。

我知道之前已经问过这个问题，但我没有弄明白答案是我在这里问的原因。任何帮助将不胜感激，谢谢。

Answer 1

在PHP中对数组进行迭代是简单的循环，但是当你表达它们时可能会有点混乱：

$myArray = [
   "foo" => "Foo",
   "bar" => "Bar"
];

所以你可以迭代一个＆＃34; tuple＆＃34;：

foreach($myArray as $key => $value) {
   print($key);
   print($value);
   print($myArray[$key]);
}

或简单的超值：

foreach($myArray as $value) {
   print($value);
}

您的情况是PHP中的经典对象迭代。由于PHP v5 PHP支持对象迭代为简单数组。

foreach($yourTinderObject->result()[0] as $contact) {
  print($contact->name);
}

正如您已经观察到的那样，我使用$yourTinderObject->result()，它是一个带有数组的函数。使用[0]密钥，我只需针对数组＆＃39; 0＆＃39;键，这是一个对象。然后，您可以使用循环值返回对象属性：$contact->_id或$contact->name。

如果对象具有带数字键的属性，例如：

，则会出现特殊情况

["arr"]=> array(1) {
      [0]=> object(stdClass)#1 (3) {
         ["abc"]=> bool(false)
         ["123"]=> int(14)
         ["123abc"]=> int(5)
      }
 }

在迭代对象

的情况下

 foareach($r[0] as $myObject){
     print($myObject->abc); // this will work
     print($myObject->{"123"}); //this will not work
     print($myObject->{"123abc"}) //this will work
 }

一个非常有趣的发现如下：

 $arr = ['abc'=>'ABC', '123'=>'123', '123abc'=>'123abc'];
 $oA = (object)$arr; //casting the array to object working in dynamic languages like PHP
 $oB = new stdClass; //create plan object
 $oB->{"123"} = "123" //setting "123" property is OK

 print($oA->{"123"}); //will not working
 print($oB->{"123"}); //will work !?!!

通常＆＃34; hack＆＃34;是之前打电话：

$myObject = json_decode($myObject, true);

然后$ myObject将多态转换为一个可以像往常一样迭代的数组。

希望有所帮助！

LL

从var_dump中提取值并将其保存在数据库中

1 个答案: