Question

我正在尝试使用ajax进行分页，但是当我点击下一页时，它会在我的控制台中显示此错误

 jquery-2.2.3.min.js:4 GET http://localhost:8000/patientPanel/ajax/patientHospital?page=2 404 (Not Found)

我也定义了我的路线，但仍然有这个错误。请在下面分享路线，控制器和视图的代码。

控制器

public function index()
{
    $hospitals = Hospital::paginate(3);
    return View::make('patientPanel/patientHospital')
        ->with('hospitals',$hospitals);
}

路线

  Route::get('/patientPanel/patientHospital', 'patientHospitalController@index');

  Route::get('ajax/patienthospital', function(){

      $hospitals = Hospital::paginate(3);

      return View::make('/patientPanel/patientHospital')
          ->with('hospitals',$hospitals)->render();
  });

查看

<section id="team">
<div class="container">
  <div class="row">

    @foreach($hospitals as $hospital)
    <div class="col-md-3 col-sm-6 col-xs-12 wow fadeIn content" data-
       wow-offset="50" data-wow-delay="1.3s">
      <div class="team-wrapper">
        <img src="/uploads/{{$hospital->picture }}" class="img-responsive" alt="team img 1" style="height: 270px; width: 500px">
          <div class="team-des">
            <h4>{{$hospital->name}}</h4>
            <span>Designer</span>
            <p>Lorem ipsum dolor sit amet, consectetur adipiscing elitquisque tempus ac eget diam et laoreet phasellus ut nisi id leo molest.</p>
          </div>
      </div>
    </div>
    @endforeach
  </div>
  {{$hospitals->links()}}
  </div>
 </section>

 <script type="text/javascript">
  $(document).on('click','.pagination a',function(e){

 e.preventDefault();
 var page = ($(this).attr('href').split('page='))[1];
 getProducts(page);
 });

 function getProducts(page)
 {
$.ajax({
   url:'/ajax/products?page='+page
}).done(function(data){

    $('.content').html(data);
    location.hash = page;
  });

 }

请告诉我为什么我收到此错误，因为我也定义了路线。

Answer 1

您将路线设为java.lang.RuntimeException: at android.app.LoadedApk.makeApplication (LoadedApk.java:563) at android.app.ActivityThread.handleBindApplication (ActivityThread.java:4540) at android.app.ActivityThread.access$1500 (ActivityThread.java:151) at android.app.ActivityThread$H.handleMessage (ActivityThread.java:1371) at android.os.Handler.dispatchMessage (Handler.java:102) at android.os.Looper.loop (Looper.java:135) at android.app.ActivityThread.main (ActivityThread.java:5268) at java.lang.reflect.Method.invoke (Method.java) at java.lang.reflect.Method.invoke (Method.java:372) at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run (ZygoteInit.java:902) at com.android.internal.os.ZygoteInit.main (ZygoteInit.java:697) Caused by: java.lang.ClassNotFoundException: at dalvik.system.BaseDexClassLoader.findClass (BaseDexClassLoader.java:56) at java.lang.ClassLoader.loadClass (ClassLoader.java:511) at java.lang.ClassLoader.loadClass (ClassLoader.java:469) at android.app.Instrumentation.newApplication (Instrumentation.java:980) at android.app.LoadedApk.makeApplication (LoadedApk.java:558)并将其设为ajax/patienthospital

从

更改网址

/patientPanel/ajax/patientHospital

到

ajax/patienthospital

或者

在路线中添加/patientPanel/ajax/patientHospital

ajax

<强>更新

我认为只有Route::get('/patientPanel/ajax/patientHospital',问题，请与/

一起使用

而不是

/ajax/patienthospital

我的控制台中出现404（未找到）错误

1 个答案: