Question

使用节点请求模块，我通过URL获取JSON数据。 JSON文件嵌套在多个级别中，而不是以可以重用的方式组织。当前的JSON看起来像这样：

{
  "data": {
    "series": {
      "brochure_image": "range.jpg",
      "background_image": "range.jpg",
      "Model 1": {
        "medium_images": "Model_1.png",
        "brand": "Tesla",
        "Model 101": {
          "medium_images": "Model_101.png",
          "brochure_image": "Model_101.png",
        },
        "Model 102": {
          "medium_images": "Model_102.png",
          "brochure_image": "Model_102.png",
        }
      },
      "Model 2": {
        "medium_images": "Model_2.png",
        "brand": "Tesla",
        "Model 201": {
          "medium_images": "Model_201.png",
          "brochure_image": "Model_201.png",
        }
      }
    }
  }
}

我想重组，以便我可以轻松地从前端访问数据。我想改变这样：

[
  {
    "series":"Model 1",
    "model": [
      {
        "modelName": "Model 101",
        "medium_images": "Model_101.png",
        "brochure_image": "Model_101.png"
      },
      {
        "modelName": "Model 102",
        "medium_images": "Model_102.png",
        "brochure_image": "Model_102.png"
      }
    ] 
  }
  {
    "series":"Model 2",
    "model": [
      {
        "modelName": "Model 201",
        "medium_images": "Model_101.png",
        "brochure_image": "Model_101.png"
      }
    ] 
  }
]

我该怎么做？我的节点server.js获取部分如下所示：

const dataUrl = "http://example.com/data/series-data.json";

// API
app.get("/api/getSeriesData", (req, res) => {
    request.get(dataUrl, (error, response, body) => {
        var json = JSON.parse(body);
        var seriesObj = json.data.series;
        var seriesArr = [];

        for (var series in seriesObj) {

            if (seriesObj.hasOwnProperty(series)) {
                seriesArr.push({"series": series, "model": seriesObj[series]});
            }
        }
        res.send(seriesArr);
    });
});

Answer 1

您可以这样做：

var obj = {
  "data": {
    "series": {
      "brochure_image": "range.jpg",
      "background_image": "range.jpg",
      "Model 1": {
        "medium_images": "Model_1.png",
        "brand": "Tesla",
        "Model 101": {
          "medium_images": "Model_101.png",
          "brochure_image": "Model_101.png",
        },
        "Model 102": {
          "medium_images": "Model_102.png",
          "brochure_image": "Model_102.png",
        }
      },
      "Model 2": {
        "medium_images": "Model_2.png",
        "brand": "Tesla",
        "Model 201": {
          "medium_images": "Model_201.png",
          "brochure_image": "Model_201.png",
        }
      }
    }
  }
};

var result = [];
Object.keys(obj.data.series).forEach(key => {
  if(key.indexOf("Model") === 0){
      var o = {series: key, model:[]};
      Object.keys(obj.data.series[key]).forEach(k => {
        if(k.indexOf("Model") === 0){
            o.model.push({modelName: k, medium_image: obj.data.series[key][k].medium_image, brochure_image: obj.data.series[key][k].brochure_image});
        }
      });
    result.push(o);
  }
});

console.log(result);

这样做是为了遍历.data.series和data.series[MODEL NAME]的所有属性，并且只考虑属性名称以模型开头的那些值。如果不是您感兴趣的所有值的属性名称都以模型开头，则此方法将不起作用。在这些情况下，您可能必须使用否定断言（检查其属性名称是否是您不感兴趣的已知属性之一）。

Answer 2

这是我的解决方案。

我们可以删除对象中不需要的keys，然后遍历对象属性并将它们添加到数组中。

如果您遇到任何问题或疑问，请通过该片段告诉我。

＆＃13;

var data = {
  "data": {
    "series": {
      "brochure_image": "range.jpg",
      "background_image": "range.jpg",
      "Model 1": {
        "medium_images": "Model_1.png",
        "brand": "Tesla",
        "Model 101": {
          "medium_images": "Model_101.png",
          "brochure_image": "Model_101.png",
        },
        "Model 102": {
          "medium_images": "Model_102.png",
          "brochure_image": "Model_102.png",
        }
      },
      "Model 2": {
        "medium_images": "Model_2.png",
        "brand": "Tesla",
        "Model 201": {
          "medium_images": "Model_201.png",
          "brochure_image": "Model_201.png",
        }
      }
    }
  }
};
var output = [];
delete data.data.series.brochure_image
delete data.data.series.background_image
for (k in data.data.series) {
  var temp = [];
  delete data.data.series[k].medium_images;
  delete data.data.series[k].brand;
  for (j in data.data.series[k]) {
    temp.push({
      modelName: j,
      medium_images: data.data.series[k][j].medium_images,
      brochure_image: data.data.series[k][j].brochure_image
    });
  }
  output.push({
    "series": k,
    model: temp
  });
}
console.log(output);

＆＃13;

 .as-console {
 height: 100%;
}
.as-console-wrapper {
  max-height: 100% !important;
  top: 0;
}

＆＃13;

节点：如何重组嵌套的JSON数据获取和组织可重用？

2 个答案: