Question

我正在尝试将表单中的数据插入mySQL DB，没有连接错误，但没有数据插入到我的数据库中。任何的想法？这是我的HTML表单：

<div class="tab-pane" id="Registration">
                    <b><em>Listen to the voice of Soul</em></b>
                    <form class="form" role="form" method="POST" action="signup.php" accept-charset="UTF-8"id="signup-nav">
                        <div class="form-group">
                            <label class="sr-only" for="email2">Email address</label>
                            <input type="email" class="form-control"id="email2" name="signup_email" placeholder="Email address" required>
                        </div>
                        <div class="form-group">
                            <label class="sr-only" for="password2">Password</label>
                            <input type="password" class="form-control" id="pwd2" name="signup_pwd" placeholder="Password" required>
                        </div>  
                        <div class="form-group">
                            <label class="sr-only" for="password3">Confirm Password</label>
                            <input type="password" class="form-control" id="pwdcon" name="signup_pwdcon" placeholder="Confirm Password" required>
                        </div>  
                        <div class="form-group">
                            <input type="submit" name="signUpBtn" value="Sign Up" class="btn btn-primary btn-block"></button>
                        </div>
                    </form>
                </div>

我的数据库名称是coldplay，table是userdata，我是使用ID = root的本地主机，没有密码

PHP：

<?php

include ("dbh.php");

if(isset($_POST["signUpBtn"])){

$signup_email = $_POST ['signup_email'];
$signup_pwd = $_POST ['signup_pwd'];
$signup_pwdcon = $_POST ['signup_pwdcon'];

$sql_signup = "insert into userdata (email, pwd, pwdcon) 
values ('$signup_email', '$signup_pwd', '$signup_pwdcon')";

mysqli_query($conn, $sql_signup);

mysqli_close($conn);

header("Location: testing.html");


}

?>

PHP数据库处理程序：

<? php

$conn = mysqli_connect("localhost", "root", "", "coldplay");

if (!$conn){
    die("Connection failed: ".mysqli_connect_error());
}

?>

Answer 1

请先阅读password hashing和how to bind parameters to prepared statements in mysqli。如果你这样做，你的脚本很容易被sql注入。

你的dbh.php文件中存在一个问题，其中包含打开的php标记。它应该读<?php <? php mysqli_query的内容（注意空格）。

如果这不是问题，您应该检查if (!mysqli_query($conn, $sql_signup)) { echo "Error: " . mysqli_error($conn); }方法的结果，如下所示：

<html>
 <body>
 <p>
    <select ng-model="selectedValue" ng-option="c1.name in c1 in c in personInfo.city"></select>
    </p>
 </body>
 >/html>

PHP没有错误，但数据没有插入数据库

1 个答案: