Sqlalchemy返回bools而不是整数

时间:2017-11-27 07:23:34

标签: python mysql sqlalchemy

不确定这里发生了什么。

表格如下:

class LogTable(Base):
    __tablename__ = 'log_table'

    id = Column(INTEGER(11), primary_key=True)
    version = Column(VARCHAR(100))
    status = Column(VARCHAR(20))

'漂亮' sql alch query。:

query = session.query(LogTable.version,
                      label('total_jobs', func.count(LogTable.version)),
                      label('success_jobs', func.sum(LogTable.status == 'SUCCESS')),
                      label('fail_jobs', func.sum(LogTable.status == 'FAILURE'))
                      ).group_by(JobLog.version)

' .all()'之前的查询值方法被调用。 ()

print(query)
SELECT log_table.version AS log_table_version, 
count(log_table.version) AS total_jobs,
sum(log_table.status = %(status_1)s) AS success_jobs,
sum(log_table.status = %(status_2)s) AS fail_jobs
FROM job_logs GROUP BY log_table.version

应该返回什么查询(并且假设您使用正确的值填充%(status_)s,并从SQL控制台返回。):

version, total_jobs, success_jobs, fail_jobs
0421f178c39df89890f97663509ce2a931a44fba,206,181,25
07e3ee0af26603c9a2543d1644742abcde664391,208,187,21
08eaf7ec41c022d77d04d108d3844fca2fa426a0,78,53,25
0cce212ddf351acfbdfae795ce0c5402e1a24540,484,314,170
15223fb4dcc4312bceac75755662a7d2eeb4fbb3,2345,1463,882
1940ad381c10fd3e7fce3e9f6e13210807e95eb8,208,164,44

由于某种原因,SQL alch正在返回:

print(query.all())
[('0421f178c39df89890f97663509ce2a931a44fba', 206, True, True), 
('07e3ee0af26603c9a2543d1644742abcde664391', 208, True, True), 
('08eaf7ec41c022d77d04d108d3844fca2fa426a0', 78, True, True), 
('0cce212ddf351acfbdfae795ce0c5402e1a24540', 484, True, True), 
('15223fb4dcc4312bceac75755662a7d2eeb4fbb3', 2345, True, True),]

1 个答案:

答案 0 :(得分:1)

在#sqlalchemy freenode过了一段时间。我被告知我需要覆盖该类型,因为我使用bool作为参数。

可以忽略对标签代码位置的更改。

这是工作解决方案。

from sqlalchemy.types import Integer
query = session.query(LogTable.version,
            func.count(LogTable.version).label('total_jobs'),
            func.sum(LogTable.status == 'SUCCESS', type_=Integer).label('success_jobs'),
            func.sum(LogTable.status == 'FAILURE', type_=Integer).label('fail_jobs'))
           .group_by(LogTable.version).order_by(desc(LogTable.create_time))