Question

我有以下字符串，我是所有变量的搜索文本顺序，但我想为$(document).ready(function(){ $('a[href*="#"]:not([href="#"])').click(function() { if (location.pathname.replace(/^\//, '') == this.pathname.replace(/^\//, '') && location.hostname == this.hostname) { var target = $(this.hash); target = target.length ? target : $('[name=' + this.hash.slice(1) + ']'); if (target.length) { $('html, body').animate({ scrollTop: target.offset().top }, 500); return false; } } }); });和string2返回true，但string3应为false。

＆＃13;

string1

＆＃13;

Answer 1

你可以这样尝试它会起作用

        var string1 = "orders"
        var string2 = "orders/pack"
        var string3 = "orders/123"
        var str = "orders/"

        var result = string1.includes(str);
        console.log(result)
        var result = string2.includes(str);
        console.log(result)
        var result = string3.includes(str);
        console.log(result)

Answer 2

你可以这样检查：

console.log( string1.includes(str) && (string1 != str) );

Answer 3

var string1 = "orders"
var string2 = "orders/pack"
var string3 = "orders/123"
var str = "/"
console.log(string1.includes(str)); //false 
console.log(string2.includes(str)); //true
console.log(string3.includes(str)); //true

你为什么不使用＆＃39; /＆＃39;而不是＆＃39;订单＆＃39;？我们不知道的任何边界？

如何检查字符串包含javascript中的子字符串

3 个答案: