从json文件javascript中删除空值

时间:2017-12-02 22:15:41

标签: javascript json

我是javascript的新手,我遇到了一个问题,我需要从json文件中删除所有空值。但我无法得到它我尝试过在网站上找到的不同方法,但它们对我不起作用。 我在下面找到的方法之一。我只是遇到一个问题,就像我在json文件之前所说的那样,我用JSON.stringify获取它并使用删除null的代码我得到了这个" {\"姓名":\"安\" ,\"儿童\":[null,{\"姓名":\" Beta \",\"儿童\&# 34;:[null,null,null]},null]}"。

function Parent(name){
    this.name = name;
    this.children=new Array(null,null,null);
}

Parent.prototype.getName = function(){
return this.name;
};

Parent.prototype.setName = function(name) { 
 this.name=name; 
};

Parent.prototype.getChildren = function(){
 return this.children;
};

Parent.prototype.setChildren = function(parent) { 
 this.children=parent; 
};

var parent = create(aux,new Parent(""));// This method create tree parent
var o = parent;
j = JSON.stringify(o, (k, v) => Array.isArray(v) 
       && !(v = v.filter(e => e !== null && e !== void 0)).length ? void 0 : v, 2 )
     alert (j);

Json文件:

{
  "name": "Ann",
  "children":
  [
    null,
    {
      "name": "Beta",
      "children":
      [
        null,
        null,
        null
      ]
    },
    null
  ]
}

我的期望:

{
  "name": "Ann",
  "children":
  [
    {
      "name": "Beta"
    }
  ]
}

1 个答案:

答案 0 :(得分:2)

JSON.parseJSON.stringify接受replacer函数来修改值:



j = '{ "name": "Ann", "children": [ null, { "name": "Beta", "children": [ null, null, null ] }, null ] }'

o = JSON.parse(j, (k, v) => Array.isArray(v) ? v.filter(e => e !== null) : v )

console.log( o )






o = { "name": "Ann", "children": [ null, { "name": "Beta", "children": [ null, null, null ] }, null ] }

j = JSON.stringify(o, (k, v) => Array.isArray(v) ? v.filter(e => e !== null) : v, 2 )

console.log( j )




要删除空数组:



o = { "name": "Ann", "children": [ null, { "name": "Beta", "children": [ null, null, null ] }, null ] }

j = JSON.stringify(o, (k, v) => Array.isArray(v) 
                                && !(v = v.filter(e => e)).length ? void 0 : v, 2 )

console.log( j )




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