Question

以下代码显示列表中最不常见的重复数字并正常工作并给出答案3 ...

    theList = [1,3,1,2,2]
listCheck, least = len(theList), 0
for theLeast in theList:
    if theList.count(theLeast) <= listCheck :
        listCheck = theList.count(theLeast)
        least = theLeast
print (least)

然而，当我定义＆amp;将列表更改为整数序列，代码表示1是最不常见的？

 def The_uncommon(integers):
    theList = integers
    listCheck, least = len(theList), 0
    for theLeast in theList:
        if theList.count(theLeast) <= listCheck :
            listCheck = theList.count(theLeast)
            least = theLeast
            return (least)
print(The_uncommon([1,3,1,2,2]))

欢迎任何建议

Answer 1

小心缩进。：）

在第一个片段中，您将遍历整个循环，而在定义函数的第二个示例中，您将返回第一个 least次。

Answer 2

python的经典缩进问题。

   def The_uncommon(integers):
        theList = integers
        listCheck, least = len(theList), 0
        for theLeast in theList:
            if theList.count(theLeast) <= listCheck :
                listCheck = theList.count(theLeast)
                least = theLeast
        return (least)
    print(The_uncommon([1,3,1,2,2]))

为什么代码体没有给出相同的结果？

2 个答案: