我已经在谷歌上呆了一段时间,但我只是难倒了。我需要解析这种性质的xml。我似乎无法跳到中间的元素,例如夹。我限制了xml,因为有很多'文件夹'元素。任何指导将不胜感激。我是在FolderID元素的属性ID之后。
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
<s:Header>
<h:ServerVersionInfo MajorVersion="14"
MinorVersion="1"
MajorBuildNumber="225"
MinorBuildNumber="46"
Version="Exchange2010_SP1"
xmlns:h="http://schemas.microsoft.com/exchange/services/2006/types"
xmlns="http://schemas.microsoft.com/exchange/services/2006/types"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema" />
</s:Header>
<s:Body xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<m:GetFolderResponse xmlns:m="http://schemas.microsoft.com/exchange/services/2006/messages"
xmlns:t="http://schemas.microsoft.com/exchange/services/2006/types">
<m:ResponseMessages>
<m:GetFolderResponseMessage ResponseClass="Success">
<m:ResponseCode>NoError</m:ResponseCode>
<m:Folders>
<t:Folder>
<t:FolderId Id="AAMkADk5MmY1ZThmLTM2MzAtNGVh" ChangeKey="AQAAABYAAACSe/NBrSZiQKqHx8yL+lIRAAAA1EWM" />
<t:ParentFolderId Id="AAMkADk5MmY1ZThmLTM2MzAtNGVh" ChangeKey="AQAAAA==" />
<t:DisplayName>Top of Information Store</t:DisplayName>
<t:TotalCount>0</t:TotalCount>
<t:ChildFolderCount>15</t:ChildFolderCount>
<t:EffectiveRights>
<t:CreateAssociated>true</t:CreateAssociated>
<t:CreateContents>true</t:CreateContents>
<t:CreateHierarchy>true</t:CreateHierarchy>
<t:Delete>true</t:Delete>
<t:Modify>true</t:Modify>
<t:Read>true</t:Read>
<t:ViewPrivateItems>true</t:ViewPrivateItems>
</t:EffectiveRights>
<t:PermissionSet>
<t:Permissions>
<t:Permission>
<t:UserId>
<t:DistinguishedUser>Default</t:DistinguishedUser>
</t:UserId>
<t:CanCreateItems>false</t:CanCreateItems>
<t:CanCreateSubFolders>false</t:CanCreateSubFolders>
<t:IsFolderOwner>false</t:IsFolderOwner>
<t:IsFolderVisible>false</t:IsFolderVisible>
<t:IsFolderContact>false</t:IsFolderContact>
<t:EditItems>None</t:EditItems>
<t:DeleteItems>None</t:DeleteItems>
<t:ReadItems>None</t:ReadItems>
<t:PermissionLevel>None</t:PermissionLevel>
</t:Permission>
<t:Permission>
<t:UserId>
<t:DistinguishedUser>Anonymous</t:DistinguishedUser>
</t:UserId>
<t:CanCreateItems>false</t:CanCreateItems>
<t:CanCreateSubFolders>false</t:CanCreateSubFolders>
<t:IsFolderOwner>false</t:IsFolderOwner>
<t:IsFolderVisible>false</t:IsFolderVisible>
<t:IsFolderContact>false</t:IsFolderContact>
<t:EditItems>None</t:EditItems>
<t:DeleteItems>None</t:DeleteItems>
<t:ReadItems>None</t:ReadItems>
<t:PermissionLevel>None</t:PermissionLevel>
</t:Permission>
</t:Permissions>
</t:PermissionSet>
<t:UnreadCount>0</t:UnreadCount>
</t:Folder>
</m:Folders>
</m:GetFolderResponseMessage>
</m:ResponseMessages>
</m:GetFolderResponse>
</s:Body>
</s:Envelope>
答案 0 :(得分:0)
你应该学习血清化。在C#中将XML转换为对象非常容易。 https://www.codeproject.com/Articles/483055/XML-Serialization-and-Deserialization-Part
那说,这将为您提供您所追求的数据。它不是非常可重复使用,并且不会帮助您使用除具有该属性的一个实例的xml文件之外的任何xml文件,但这就是您所追求的内容。
string FolderId;
string ChangeKey;
using (StreamReader sr = new StreamReader("c:\\myfile.xml"))
{
string line;
while ((line = sr.ReadLine()) != null)
{
if (line.Contains("<t:FolderId Id="))
{
try
{
var lineArray = line.Split('\"');
FolderId = lineArray[1];
ChangeKey = lineArray[3];
}
catch
{
// handle exception
}
}
}
}
答案 1 :(得分:0)
您可以使用XSD.exe创建架构类。然后使用XML反序列化器,您可以反序列化/解析xml到对象
答案 2 :(得分:0)
LINQ to XML是最好的.NET XML Parsing API。 看到 https://docs.microsoft.com/en-us/dotnet/csharp/programming-guide/concepts/linq/xdocument-class-overview
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml.Linq;
namespace ConsoleApp12
{
class Program
{
static void Main(string[] args)
{
var doc = XDocument.Load(@"c:\temp\foo.xml");
var ns = (XNamespace)"http://schemas.microsoft.com/exchange/services/2006/types";
var folders = doc.Descendants(ns + "Folder");
foreach (var e in folders)
{
var folderId = e.Element(ns + "FolderId").Attribute("Id").Value;
Console.WriteLine(folderId);
}
Console.WriteLine("Hit any key to exit.");
Console.ReadKey();
}
}
}
答案 3 :(得分:-1)
使用xml linq
XDocument doc = XDocument.Load(FILENAME);
List<XElement> folders = doc.Descendants().Where(x => x.Name.LocalName == "Folder").ToList();
XNamespace tNs = folders.FirstOrDefault().GetNamespaceOfPrefix("t");
XElement id_AAMkADk5MmY1ZThmLTM2MzAtNGVh = folders.Where(x => (string)x.Element(tNs + "FolderId").Attribute("Id") == "AAMkADk5MmY1ZThmLTM2MzAtNGVh").FirstOrDefault();