用Scipy解决一组ODE

时间:2017-12-06 02:30:07

标签: python scipy ode differential-equations

我正在尝试开发一种算法(使用scipy.integrate.odeint())来预测细胞,基质和产品(即,)随时间的变化浓度,直到系统达到稳态(~100或200小时) 。生物反应器中细胞的初始浓度为0.1 /,最初反应器中没有葡萄糖或产物。我想测试一系列不同流速的算法,在0.01 /ℎ和0.25 / between之间,并分析流速对产品生产的影响(即⋅in/ℎ)。最后,我想生成一个图表,显示产品生产率(y轴)与流速,在x轴上。我的目标是估算导致最大(或关键)生产率的流速。到目前为止,这是我的代码:

from scipy.integrate import odeint
import numpy as np

# Constants
u_max = 0.65
K_s = 0.14
K_1 = 0.48
V = 2
X_in = 0
S_in = 4
Y_s = 0.38
Y_p = 0.2

# Variables
# Q - Flow Rate (L/h), value between 0.01 and 0.25 that produces best Q * P
# X - Cell Concentration (g/L)
# S - The glucose concentration (g/L)
# P - Product Concentration (g/L)

# Equations
def func_dX_dt(X, t, S):
    u = (u_max) / (1 + (K_s / S))
    dX_dt = (((Q * S_in) - (Q * S)) / V) + (u * X)
    return dX_dt

def func_dS_dt(S, t, X):
    u = (u_max) / (1 + (K_s / S))
    dS_dt = (((Q * S_in) - (Q * S)) / V) - (u * (X / Y_s))
    return dS_dt

def func_dP_dt(P, t, X, S):
    u = (u_max) / (1 + (K_s / S))
    dP_dt = ((-Q * P) / V) - (u * (X / Y_p))
    return dP_dt

t = np.linspace(0, 200, 200)

# Q placeholder
Q = 0.01

# Attempt to solve the Ordinary differential equations
sol_dX_dt = odeint(func_dX_dt, 0.1, t, args=(S,))
sol_dS_dt = odeint(func_dS_dt, 0.1, t, args=(X,))
sol_dP_dt = odeint(func_dP_dt, 0.1, t, args=(X,S))

在程序当前状态中,似乎没有办法为P生成稳态值。我试图进行此修改以获得X的值。

sol_dX_dt = odeint(func_dX_dt, 0.1, t, args=(odeint(func_dS_dt, 0.1, t, args=(X,)),))

它产生错误:

NameError: name 'X' is not defined

此时我不确定如何继续前进。

(编辑1:添加原始方程式)

第一个等式

第二个等式和第三个等式

1 个答案:

答案 0 :(得分:1)

您不必将函数应用于每个部分,而是返回衍生元组,如下所示:

import numpy as np
from scipy.integrate import odeint
import matplotlib.pyplot as plt

Q = 0.01
V = 2
Ys = 0.38
Sin = 4
Yp = 0.2
Xin = 0
umax = 0.65
Ks = 0.14
K1 = 0.48

def mu(S, umax, Ks, K1):
    return umax/((1+Ks/S)*(1+S/K1))

def dxdt(x, t, *args):
    X, S, P = x
    Q, V, Xin, Ys, Sin, Yp, umax, Ks, K1 = args
    m = mu(S, umax, Ks, K1)
    dXdt = (Q*Xin - Q*X)/V + m*X
    dSdt = (Q*Sin - Q*S)/V - m*X/Ys
    dPdt = -Q*P/V - m*X/Yp
    return dXdt, dSdt, dPdt

t = np.linspace(0, 200, 200)
X0 = 0.1
S0 = 0.1
P0 = 0.1
x0 = X0, S0, P0
sol = odeint(dxdt, x0, t, args=(Q, V, Xin, Ys, Sin, Yp, umax, Ks, K1))

plt.plot(t, sol[:, 0], 'r', label='X(t)')
plt.plot(t, sol[:, 1], 'g', label='S(t)')
plt.plot(t, sol[:, 2], 'b', label='P(t)')
plt.legend(loc='best')
plt.xlabel('t')
plt.grid()
plt.show()

输出:

enter image description here

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