Question

我有下表

AdviserName
-----------
Tearle, Michael Hearn
Hearn Tearle, Michael
Van Der Welden, Luke
Welden, Luke Van Der
Brennan, Sony G
G Brennan, Sony
Rhammasamysundaran, Vishnu Brahma Kuma 
Brahma Kuma Rhammasamysundaran, Vishnu

基本上我需要重新安排，所以它成为FirstName MiddleName LastName。例如Michael Hearn Tearle或Sony G Brennan或Luke Van Der Welden。

我使用了下面的语法但不知何故它不喜欢中间名是否像Hearn Tearle，Michael这样的逗号。

If(OBJECT_ID('tempdb..#tempX') Is Not Null)

Drop Table #tempX

create table #tempX (AdviserName varchar(max))

insert into #tempX (AdviserName)
values ('Tearle, Michael Hearn'),('Hearn Tearle, Michael'),('Van Der Welden, Luke'),('Welden, Luke Van Der'),('Brennan, Sony G'),('G Brennan, Sony'),('Rhammasamysundaran, Vishnu Brahma Kuma '), ('Brahma Kuma Rhammasamysundaran, Vishnu ')

--select * from #tempX


select substring(advisername, charindex(',', replace(advisername, ' ', '')) + 1, len(advisername))+' '+ left(advisername, charindex(',', advisername) -1) as AdviserName from #tempX

以下是结果。

AdviserName
--------------------------------------
 Michael Hearn Tearle
, Michael Hearn Tearle
n, Luke Van Der Welden
 Luke Van Der Welden
 Sony G Brennan
, Sony G Brennan
 Vishnu Brahma Kuma  Rhammasamysundaran
n, Vishnu  Brahma Kuma Rhammasamysundaran

如何在逗号之前和逗号之后进行查询以满足中间名？

我正在使用SQL Server 2012.

谢谢大家。

Answer 1

试试这个

If(OBJECT_ID('tempdb..#tempX') Is Not Null)

Drop Table #tempX

create table #tempX (AdviserName varchar(max))

insert into #tempX (AdviserName)
values ('Tearle, Michael Hearn'),('Hearn Tearle, Michael'),('Van Der Welden, Luke'),('Welden, Luke Van Der'),('Brennan, Sony G'),('G Brennan, Sony'),('Rhammasamysundaran, Vishnu Brahma Kuma '), ('Brahma Kuma Rhammasamysundaran, Vishnu ')


select
    AdviserName,
    replace(replace(
    SUBSTRING(AdviserName,charindex(',',AdviserName),len(AdviserName))
    +' '+
     SUBSTRING(AdviserName,1,charindex(',',AdviserName))    
     ,',',''),'  ',' ')
from #tempX

Answer 2

;with d as
(select AdviserName, charindex(',',AdviserName) as comma from #tempX)
select
ltrim(rtrim(substring(advisername,comma+1,100)))+' '+ltrim(rtrim(left(advisername,comma-1)))
from d

逗号之前和之后的字符串交换

2 个答案: