Question

我有一个查询如下问题在结果中我希望它按照特定周的TESTTool和Release版本进行分组。因此，如果我输入一系列日期，那么我应该根据发布版本和Testtool获取该周的testtool，Releaseversion，Week No，TotalNoscripts，Pass和fail百分比。但是如果我提供按日期分组的日期范围，那么我不想。

select TestTool,ReleaseVersion,WeekNo=DATEPART(wk,StartDate),YearNo=DATEPART(year,StartDate),
totalnoofscripts=count(ScriptName),PassPercentage=round(avg(case when Status='Pass' then 100.0 else 0.0 end), 2),
 FailPercentage=round(avg(case when Status='Fail' then 100.0 else 0.0 end), 2) 
 from CitraTestLogging.dbo.TestScript as s1,CitraTestLogging.dbo.TestRun as s2 
 where  s1.TestRun_ID=s2.ID and StartDate between '2017-12-01' and '2017-12-08'
 group by TestTool,ReleaseVersion,StartDate order by TestTool,ReleaseVersion,StartDate;

QueryResult TableStructure

Answer 1

您只需要从组中删除startdate。

我在订单中添加了年份和星期，以便您获得订购的结果。任何格式化你的SQL！

SELECT TestTool
    ,ReleaseVersion
    ,WeekNo = DATEPART(wk, StartDate)
    ,YearNo = DATEPART(year, StartDate)
    ,totalnoofscripts = count(ScriptName)
    ,PassPercentage = round(avg(CASE 
                WHEN STATUS = 'Pass'
                    THEN 100.0
                ELSE 0.0
                END), 2)
    ,FailPercentage = round(avg(CASE 
                WHEN STATUS = 'Fail'
                    THEN 100.0
                ELSE 0.0
                END), 2)
FROM CitraTestLogging.dbo.TestScript AS s1
    ,CitraTestLogging.dbo.TestRun AS s2
WHERE s1.TestRun_ID = s2.ID
    AND StartDate BETWEEN '2017-12-01'
        AND '2017-12-08'
GROUP BY TestTool
    ,ReleaseVersion
    ,DATEPART(year, StartDate)
    ,DATEPART(wk, StartDate)
ORDER BY TestTool
    ,ReleaseVersion
    ,DATEPART(year, StartDate)
    ,DATEPART(wk, StartDate);

查询基于group by查找结果

1 个答案: