Question

我有一个json文件，它存储在环境变量temp。

中

{ "users": [ { "username": "jack", "email": "jack@somewhere.com", "total running apps": "1", "api-mock-app": "0", "flogo": "1", "ipaas": "0", "nodejs-app": "0" }, { "username": "jill", "email": "jill@somewhere.com", "total running apps": "1", "api-mock-app": "0", "flogo": "1", "ipaas": "0", "nodejs-app": "0" } ] } 当我使用此命令将此JSON转换为CSV时

jq -r '.users[] | [.username, .email, .total running apps, .api-mock-app, .flogo, .ipaas, .nodejs-app] | @csv' <<< $temp

我收到了以下错误。

jq：错误：语法错误，意外IDENT（Unix shell引用问题？）at第1行： .users [] | [.username，.email，.total正在运行的应用，.api-mock-app，.flogo，.ipaas，.nodejs-app] | @csv
jq：1编译错误

请帮忙吗？

Answer 1

您需要引用列名，特别是因为它们包含空格和短划线。但是你需要转义bash的引号：

jq --raw-output '.users[] | [.username, .email, ."total running apps", ."api-mock-app", ."flogo", ."ipaas", ."nodejs-app"] | @csv'

Answer 2

我得到了这个有效的代码click here

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
<html>
<head>
    <title>Demo - Covnert JSON to CSV</title>
    <script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
    <script type="text/javascript" src="https://github.com/douglascrockford/JSON-js/raw/master/json2.js"></script>

    <script type="text/javascript">
        // JSON to CSV Converter
        function ConvertToCSV(objArray) {
            var array = typeof objArray != 'object' ? JSON.parse(objArray) : objArray;
            var str = '';

            for (var i = 0; i < array.length; i++) {
                var line = '';
                for (var index in array[i]) {
                    if (line != '') line += ','

                    line += array[i][index];
                }

                str += line + '\r\n';
            }

            return str;
        }

        // Example
        $(document).ready(function () {

            // Create Object
            var items = [
                  { name: "Item 1", color: "Green", size: "X-Large" },
                  { name: "Item 2", color: "Green", size: "X-Large" },
                  { name: "Item 3", color: "Green", size: "X-Large" }];

            // Convert Object to JSON
            var jsonObject = JSON.stringify(items);

            // Display JSON
            $('#json').text(jsonObject);

            // Convert JSON to CSV & Display CSV
            $('#csv').text(ConvertToCSV(jsonObject));
        });
    </script>
</head>
<body>
    <h1>
        JSON</h1>
    <pre id="json"></pre>
    <h1>
        CSV</h1>
    <pre id="csv"></pre>
</body>
</html>

＆＃13;

check out this link

使用jq将JSON转换为CSV

2 个答案: