我试图在我的php网站上安装此程序。我试着阅读很多主题,但是没有用。 PHP代码不起作用。 谢谢你的帮助!
这是我的存储过程:
CREATE DEFINER=`dba233`@`%%` PROCEDURE `sp_IncluUser`(IN u_Name TEXT, IN u_Email TEXT, IN u_CodAcess TEXT, OUT Result boolean, Out Message TEXT, OUT QtCli int)
BEGIN
Declare QtClient Int;
Declare QtUser Int;
Declare Erro boolean default False;
DECLARE exepction SMALLINT DEFAULT 0;
DECLARE CONTINUE HANDLER FOR SQLEXCEPTION SET excessao = 1;
SET Result = True;
SELECT COUNT(*) into QtdeCliente
FROM Nuvem_Client
WHERE u_CodAcesso = Cod_Acesso;
IF (QtdeClient = 0) THEN
SET Result = False;
SET Message = 'Acess code invalid.';
END IF;
Set QtCli = 999;
IF Result = True THEN
SELECT COUNT(*) into QtdeUsuario
FROM Nuvem_Users
WHERE Email = u_Email;
Set QtCli = QtdeUsuario;
IF (QtdeUsuario > 0) THEN
SET Result = False;
SET Message = 'Email already registered';
END IF;
END IF;
IF Result = True THEN
IF (u_Nome = "" OR u_Email = "") THEN
SET Result = False;
SET Message = 'Invalid';
END IF;
END IF;
IF Result = True THEN
START TRANSACTION;
INSERT INTO db_Users ( `Name`, `Name_user`, `Email`, `password`, `Cod_Tipo_User`, `DtInclusao`)
VALUES ( u_Name, u_Name, u_Email, '', '6', Now());
IF excessao = 1 THEN
SET Result = False;
SET Message = 'Error';
ROLLBACK;
ELSE
SELECT DISTINCT LAST_INSERT_ID() INTO @idUsuario FROM Nuvem_Users;
IF excessao = 1 THEN
SET Result = False;
SET Message = 'Error';
ROLLBACK;
ELSE
Insert into Nuvem_Users_Unity (Cod_User, Cod_Unity)
(SELECT @idUsuar, Cod_Unidade FROM Nuvem_Unity_Client UniCli
inner join Nuvem_Client Cli on UniCli.Cod_business = Cli.Cod_Empresa
where Cli.Cod_Acess = u_CodAcess);
IF excessao = 1 THEN
SET Result = False;
SET Message = 'error' ;
ROLLBACK;
ELSE
SET Result = True;
SET Message = 'successfull ';
COMMIT;
END IF;
END IF;
END IF;
END IF;
END
表和其他东西的名称有很多错误。这是因为我想为我保留信息,因为它来自客户。 我会改变一切,没问题......我只是想知道我需要运行这个程序的PHP代码。我不想知道答案,你可以给我一个提示,我会去搜索。
谢谢你们!我需要你的帮助。