如果JS中的语句语法错误

Question

我正在尝试使用if / else，但我无法弄清楚我的语法出错了。如果payload不是school_ids，我希望role仅提交p_admin。谢谢您的帮助！

const createUser = (payload) => request.postJSON(
    '/register',
    excludeObjNullValue({
        username: payload.username,
        email: payload.email,
        password: payload.password,
        first_name: payload.firstName,
        last_name: payload.lastName,
        role: payload.role,
        district_id: payload.districtId,
        if (role !== 'p_admin'){
        school_ids: payload.schoolIds
        }
    })
);

Answer 1

我会看到2-3个选项，具体取决于您的excludeObjNullValue功能：

1. 您可以将该表达式分解为几个语句，或者

2. 或使用属性扩展表示法和条件运算符，或

3. 如果excludeObjNullValue符合名称的建议，您可以使用条件而不使用点差表示法，并依靠excludeObjNullValue将其排除

选项3可能是您最好的选择，但我会按顺序给出它们：

选项1：多语句方式：

const createUser = (payload) => {
    const options = {
        username: payload.username,
        email: payload.email,
        password: payload.password,
        first_name: payload.firstName,
        last_name: payload.lastName,
        role: payload.role,
        district_id: payload.districtId,
    };
    if (role !== 'p_admin') {
        options.school_ids = payload.schoolIds;
    }
    return request.postJSON('/register', excludeObjNullValue(options));
};

选项2：财产价差和条件运算符

Property spread是一个第3阶段的提案，但对它的支持已经在Chrome和Firefox中发布，如果您正在进行转换，您可以告诉您的转发器支持它。这看起来像这样：

const createUser = (payload) => request.postJSON(
    '/register',
    excludeObjNullValue({
        username: payload.username,
        email: payload.email,
        password: payload.password,
        first_name: payload.firstName,
        last_name: payload.lastName,
        role: payload.role,
        district_id: payload.districtId,
        {...(role !== 'p_admin' ? {school_ids: payload.schoolIds} : {}}
        }
    })
);

即使您的电话受到支持，这是否是一个好主意。 :-)它会简要地创建一个额外的对象和迭代器。

选项3：依靠excludeObjNullValue排除null值的属性：

如果它确实符合名称的建议，那么如果我们为其赋予值school_ids，它将会删除null。所以：

const createUser = (payload) => request.postJSON(
    '/register',
    excludeObjNullValue({
        username: payload.username,
        email: payload.email,
        password: payload.password,
        first_name: payload.firstName,
        last_name: payload.lastName,
        role: payload.role,
        district_id: payload.districtId,
        school_ids: role !== 'p_admin' ? payload.schoolIds : null
        }
    })
);

Answer 2

您无法在对象声明中编写if语句。您还需要为箭头函数明确定义body。所以你可以做类似

的事情

const createUser = (payload) => {
   const obj = {
      username: payload.username,
        email: payload.email,
        password: payload.password,
        first_name: payload.firstName,
        last_name: payload.lastName,
        role: payload.role,
        district_id: payload.districtId
   };

   if(obj.role !== 'p_admin') {
      obj.school_ids = payload.schoolIds
   }

   return request.postJSON('/register', excludeObjNullValue(obj));

}