EF4 CTP5多态查询

时间:2011-01-23 09:03:35

标签: entity-framework entity-framework-4 code-first ef-code-first entity-framework-ctp5

我有一个如下模型:

public class Employee
{
    public Employee()
    {
        TimeCards = new List<TimeCard>();
    }
    public int Id { get; set; }
    public string Name { get; set; }
    public DateTime HireDate { get; set; }
    public virtual ICollection<TimeCard> TimeCards { get; set; }
}
public class Manager : Employee
{
    public bool HasCompanyCar { get; set; }
}
public class Developer : Employee
{
    public string MainProgrammingLanguage { get; set; }
}

(如果重要,我正在使用this infrastructure。)

我需要的是让所有非经理的员工。只有一个OfType扩展方法。我需要的是NotOfType。

    var employees = unitOfWork.Employees
                   .FindAll()
                   .NotOfType<Manager>(); //or something similar
    var cards = unitOfWork.TimeCards.FindAll();

    var query = from e in employees
                from tc in cards
                where tc.Employee.Id == e.Id && e.Name.StartsWith("C")
                select tc;

偏离主题:继承是这种情况的正确选择吗?你是如何建模的?我只是觉得继承导致我走错了路。

1 个答案:

答案 0 :(得分:0)

也许您会发现NotOfType扩展方法应该更好,但这应该适合您。

var employees = unitOfWork.Employees
               .Where(e => !(e is Manager));

var cards = unitOfWork.TimeCards.FindAll();

var query = from e in employees
            from tc in cards
            where 
               tc.Employee.Id == e.Id && 
               e.Name.StartsWith("C")                   
            select tc;

或者像这样:

var employees = unitOfWork.Employees
               .FindAll();

var cards = unitOfWork.TimeCards.FindAll();

var query = from e in employees
            from tc in cards
            where 
               tc.Employee.Id == e.Id && 
               !(e is Manager) &&
               e.Name.StartsWith("C")                   
            select tc;