Question

如何选择具有精确子序列id的行？例如，我只需要选择具有subcat_id 2,6或2,4,5,7的行。

CREATE TABLE IF NOT EXISTS `testing123` (
  `id` int(10) NOT NULL AUTO_INCREMENT,
  `cat_id` int(10) DEFAULT '0',
  `subcat_id` int(10) DEFAULT '0',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=223 DEFAULT CHARSET=utf8;

REPLACE INTO `testing123` (`id`, `cat_id`, `subcat_id`) VALUES
    (170, 32, 5),
    (171, 33, 1),
    (172, 33, 7),
    (173, 34, 5),
    (175, 35, 2),
    (176, 36, 1),
    (177, 36, 2),
    (178, 36, 7),
    (179, 37, 2),
    (180, 37, 6),
    (184, 40, 2),
    (185, 40, 5),
    (186, 40, 6),
    (187, 41, 4),
    (188, 54, 2),
    (189, 54, 4),
    (190, 54, 5),
    (191, 54, 7),
    (192, 55, 6),
    (193, 56, 2),
    (194, 56, 6),
    (195, 57, 6),
    (196, 58, 1),
    (197, 59, 3),
    (198, 60, 6),
    (199, 61, 2),
    (200, 61, 6),
    (203, 63, 1),
    (204, 63, 6),
    (205, 64, 2),
    (206, 64, 6),
    (207, 65, 1),
    (208, 65, 2),
    (209, 66, 4),
    (214, 67, 1),
    (215, 67, 5),
    (220, 70, 1),
    (221, 70, 4),
    (222, 70, 5);

如果我正在使用OR或IN（），它会选择所有行，其中有任何一个提供了子序列，但我只需要完全匹配。

为实验提供的表格示例。

帮助！：）

Answer 1

SELECT *
  FROM testing123
 WHERE cat_id IN (SELECT cat_id
                    FROM testing123
                   WHERE subcat_id IN (2, 6)
                GROUP BY cat_id
                  HAVING COUNT(*) = 2)


SELECT *
  FROM testing123
 WHERE cat_id IN (SELECT cat_id
                    FROM testing123
                   WHERE subcat_id IN (2, 4, 5, 7)
                GROUP BY cat_id
                  HAVING COUNT(*) = 4)

请注意COUNT(*) = N子句取决于IN()

中枚举的子系数的数量

Mysql复杂选择

1 个答案: