如何使用pandas计算滚动窗口的标准偏差

时间:2017-12-10 12:40:51

标签: pandas

这是我的数据,我从20170101到20170106交易了三个符号 并记录每个符号重新获利。

label = ['symbol','date','relized']
list = [['S1','20170101',11111],['S1','20170102',12221],['S1','20170103',33445],['S2','20170102',-32421],['S2','20170103',-12211],['S2','20170104',9331],['S2','20170105',62211],['S2','20170106',92211],['S3','20170102',20444]]

df = pd.DataFrame(list,columns=label)

  symbol      date  relized
0     S1  20170101    11111
1     S1  20170102    12221
2     S1  20170103    33445
3     S2  20170102   -32421
4     S2  20170103   -12211
5     S2  20170104     9331
6     S2  20170105    62211
7     S2  20170106    92211
8     S3  20170102    20444

所以,如果今天是20170103,那么总重新为33445 +( - 12211)+20444,

我想做的是,我的初始资本(参数名称:C)是500000,我想计算值R,公式是

R=Std(C + TodayTotalRelized,period=3Days)/Average(Std value of nearly 3 Day, period=3Days)

有什么好方法吗?

1 个答案:

答案 0 :(得分:0)

您可以使用滚动功能。

df.rolling(windows=3).std()
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