TypeError ...不是函数

时间:2017-12-10 16:19:33

标签: gulp gulp-task

我已按如下方式安装了gulp-run-command:

npm install gulp-run-command

我正在执行一系列gulp任务。所有其他人都在工作,除了这一个。这是我运行gulp-run-command的任务:

var gulp = require('gulp');
var run = require('gulp-run-command');

gulp.task('testTask', run('testString'));

直接来自gulp-run-command的基本用法,如下所示: https://www.npmjs.com/package/gulp-run-command#usage

我运行gulp时出现以下错误:

TypeError: run is not a function
    at Object.<anonymous> (c:\mypath\gulp\tasks\common\initLocalJsonSe
rver.js:6:23)
    at Module._compile (module.js:570:32)
    at Object.Module._extensions..js (module.js:579:10)
    at Module.load (module.js:487:32)
    at tryModuleLoad (module.js:446:12)
    at Function.Module._load (module.js:438:3)
    at Module.require (module.js:497:17)
    at require (internal/module.js:20:19)
    at requireDir (c:\mypath\node_modules\require-dir\index.js:123:33)

    at requireDir (c:\mypath\node_modules\require-dir\index.js:76:33)

这里有什么问题?

1 个答案:

答案 0 :(得分:0)

好的,我在行末添加var run = require('gulp-run-command');时有效:var run = require('gulp-run-command').default

所以,就像这样:

arr[0]
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