如何公开声明和使用listbox变量?

时间:2017-12-10 23:18:48

标签: vba excel-vba excel

我没有为许多列表框(格式相同)编写单独的代码,而是尝试使用通用代码来执行一组操作:

首先,我在模块名称" GLOBALS"中声明了全局变量:

Public glb As Listbox

名为" SCHEDULES" (包含列表框),当我点击列表框时,我有这个代码来设置全局列表框变量:

Private Sub ListBox1_Click()
glb = SCHEDULE.ListBox1 <<<<<<<<<THIS IS WHERE I GET MY ERROR
End Sub

当我按下删除时,我想调用名为DeleteLBItem的代码(删除所选行,然后将所有较低的行向上移动:

Private Sub ListBox1_KeyDown(ByVal KeyCode As MSForms.ReturnInteger, ByVal Shift As Integer)

If KeyCode = 46 Then
If MsgBox("Clear selected event info?", vbOKCancel, "Confirm Event Action") = vbCancel Then
Exit Sub
Else
Call DeleteLBItem
End If
End If
End Sub` `

程序DeleteLBItem位于单独的模块标题中,#34; CORE&#34;:

Sub DeleteLBItem()
Dim i As Integer

i = glb.ListIndex

Do Until i = glb.ListCount - 1
With glb
.List(i, 0) = .List(i + 1, 0)
.List(i, 1) = .List(i + 1, 1)
.List(i, 2) = .List(i + 1, 2)
End With
n = n + 1
Loop
With glb
.List(.ListCount, 0) = ""
.List(.ListCount, 1) = ""
.List(.ListCount, 2) = ""
End With
End Sub

我得到的错误是运行时间13(类型不匹配)。我需要做些什么呢?

2 个答案:

答案 0 :(得分:1)

您有多个列表框(例如:LB1,LB2,LB3),并且您正在为每个列表框的事件中添加代码。

' set the global listbox to the clicked one (pseudo-code)
Private Sub LB1_Click()
GLB = LB1
End Sub
Private Sub LB2_Click()
GBL = LB2
End Sub
Private Sub LB3_Click()
GLB = LB3
End Sub

并且您还要向keydown添加内容以执行您的删除子。

我没有尝试过使用这样的全局对象,但它似乎并不适合你。在执行sub时只传递对象的引用会更简单。

Private Sub ListBox1_KeyDown(ByVal KeyCode As MSForms.ReturnInteger, ByVal Shift As Integer)
   If KeyCode = 46 Then
      If MsgBox("Clear selected event info?", vbOKCancel, "Confirm Event Action") = vbCancel Then
         Exit Sub
      Else
         DeleteLBItem ListBox1 ' dont need brackets here!
      End If
   End If
End Sub

Sub DeleteLBItem(ByRef LB As Object)
Dim i As Integer

   i = LB.ListIndex

   Do Until i = LB.ListCount - 1
      With LB
         .List(i, 0) = .List(i + 1, 0)
         .List(i, 1) = .List(i + 1, 1)
         .List(i, 2) = .List(i + 1, 2)
      End With
      i = i + 1 ' this was n?
   Loop
   With LB
      .List(.ListCount, 0) = ""
      .List(.ListCount, 1) = ""
      .List(.ListCount, 2) = ""
   End With
End Sub

我没有对其进行测试,但假设它有效,您不再需要代码来在click事件中分配全局列表框。

答案 1 :(得分:0)

@ YowE3K感谢您的建议。我从来没有真正理解参数的传递或故意使用它们,所以我做了一些研究,我设法修复了代码

此代码以下列形式出现:

Private Sub ListBox1_KeyDown(ByVal KeyCode As MSForms.ReturnInteger, ByVal Shift As Integer)
If KeyCode = 46 Then
DeleteLBItemSchedule ListBox1
Else
End If
End Sub

此代码显示在单独的模块中:

Sub DeleteLBItemSchedule(glb As MSForms.Listbox)
Dim i As Integer
i = glb.ListIndex

Do Until i = glb.ListCount - 1
With glb
.List(i, 0) = .List(i + 1, 0)
.List(i, 1) = .List(i + 1, 1)
.List(i, 2) = .List(i + 1, 2)
End With
i = i + 1
Loop
With glb
.List(.ListCount - 1, 0) = ""
.List(.ListCount - 1, 1) = ""
.List(.ListCount - 1, 2) = ""
End With

End Sub
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