Symfony如何在测试中跳过某些行

Question

我从Symfony 2.8中看到了一些非常奇怪的行为。我已经在一些标准的Symfony类中添加了一些echo和var_dump来尝试找出正在进行的操作。

这个Application类扩展了下一个类。我添加了四个echo和一个var_dump，它们是半缩进的：

vendor/symfony/symfony/src/Symfony/Bundle/FrameworkBundle/Console/Application.php

<?php

namespace Symfony\Bundle\FrameworkBundle\Console;

use Symfony\Component\Console\Application as BaseApplication;

class Application extends BaseApplication
{
    private $kernel;

    public function __construct(KernelInterface $kernel)
    {
      echo "Construct Symfony\Bundle\FrameworkBundle\Console\Application\n";
      echo get_class($this) . PHP_EOL;
      echo get_parent_class($this) . PHP_EOL;
        $this->kernel = $kernel;
      var_dump('Symfony', Kernel::VERSION.' - '.$kernel->getName().'/'.$kernel->getEnvironment().($kernel->isDebug() ? '/debug' : ''));

        parent::__construct('Symfony', Kernel::VERSION.' - '.$kernel->getName().'/'.$kernel->getEnvironment().($kernel->isDebug() ? '/debug' : ''));

        $this->getDefinition()->addOption(new InputOption('--shell', '-s', InputOption::VALUE_NONE, 'Launch the shell.'));
        $this->getDefinition()->addOption(new InputOption('--process-isolation', null, InputOption::VALUE_NONE, 'Launch commands from shell as a separate process.'));
        $this->getDefinition()->addOption(new InputOption('--env', '-e', InputOption::VALUE_REQUIRED, 'The Environment name.', $kernel->getEnvironment()));
        $this->getDefinition()->addOption(new InputOption('--no-debug', null, InputOption::VALUE_NONE, 'Switches off debug mode.'));
      echo "Finished constructing Symfony\Bundle\FrameworkBundle\Console\Application\n";
    }

这是基础Application类。我只在这个类中添加了echo，这也是半缩进的：

vendor/symfony/symfony/src/Symfony/Component/Console/Application.php

<?php

namespace Symfony\Component\Console;

class Application
{
    private $name;
    private $version;
    private $definition;
    private $helperSet;
    private $defaultCommand;

    public function __construct($name = 'UNKNOWN', $version = 'UNKNOWN')
    {
      echo "--> Construct Symfony\Component\Console\Application\n";
        $this->name = $name;
        $this->version = $version;
        $this->defaultCommand = 'list';
        $this->helperSet = $this->getDefaultHelperSet();
        $this->definition = $this->getDefaultInputDefinition();

        foreach ($this->getDefaultCommands() as $command) {
            $this->add($command);
        }
    }

当我运行php app/console hmrx:app:filecheck时，我明白了：

Construct Symfony\Bundle\FrameworkBundle\Console\Application
Symfony\Bundle\FrameworkBundle\Console\Application
Symfony\Component\Console\Application
C:\server\Apache24\htdocs\dev.hmr-app\hmrex\HMRX_App\vendor\symfony\symfony\src\Symfony\Bundle\FrameworkBundle\Console\Application.php:44:
string(7) "Symfony"
C:\server\Apache24\htdocs\dev.hmr-app\hmrex\HMRX_App\vendor\symfony\symfony\src\Symfony\Bundle\FrameworkBundle\Console\Application.php:44:
string(21) "2.8.2 - app/dev/debug"
--> Construct Symfony\Component\Console\Application
Finished constructing Symfony\Bundle\FrameworkBundle\Console\Application

当我通过测试运行相同的代码时，我得到了这个：

Construct Symfony\Bundle\FrameworkBundle\Console\Application
Symfony\Bundle\FrameworkBundle\Console\Application
Symfony\Component\Console\Application
C:\server\Apache24\htdocs\dev.hmr-app\hmrex\HMRX_App\vendor\symfony\symfony\src\Symfony\Bundle\FrameworkBundle\Console\Application.php:44:
string(7) "Symfony"
C:\server\Apache24\htdocs\dev.hmr-app\hmrex\HMRX_App\vendor\symfony\symfony\src\Symfony\Bundle\FrameworkBundle\Console\Application.php:44:
string(21) "2.8.2 - app/dev/debug"
Finished constructing Symfony\Bundle\FrameworkBundle\Console\Application

请注意除了第二行--> Construct Symfony\Component\Console\Application之外的输出是相同的，当作为测试的一部分运行时，它会丢失。似乎parent::__construct('Symfony', Kernel::VERSION.' - '.$kernel->getName().'/'.$kernel->getEnvironment().($kernel->isDebug() ? '/debug' : ''));没有运行。 PHP / Symfony如何可能跳过运行没有条件的行？