我试图获取所有Currency
个对象,其中Ticker
个对象嵌套在每个货币对象中。到目前为止,我只能用里面的货币对象获取代码,但这真的不方便吗?我不确定我需要做些什么来实现以下输出
所以我想要的是这样的东西:
[
{
"id": 1,
"name": "Dollar",
"symbol": "USD"
"ticker": [
{
"id": 1,
"rank": 1,
"price_dkk": 123.25
}
]
}
]
模型
class Currency(models.Model):
symbol = models.CharField(max_length=4, default='BTC', unique=True)
name = models.CharField(max_length=20, default='Bitcoin', unique=True)
img = models.ImageField(upload_to = 'static/img/currencies', blank=True)
is_active = models.BooleanField(default=False)
class Meta:
verbose_name_plural = _('currencies')
def __str__(self):
return self.name
class Ticker(models.Model):
currency = models.ForeignKey('Currency', on_delete=models.CASCADE)
rank = models.IntegerField()
price_dkk = models.DecimalField(max_digits=20, decimal_places=6)
market_cap_dkk = models.BigIntegerField()
percent_change_1h = models.DecimalField(max_digits=4, decimal_places=2)
percent_change_24h = models.DecimalField(max_digits=4, decimal_places=2)
percent_change_7d = models.DecimalField(max_digits=4, decimal_places=2)
created_at = models.DateTimeField(auto_now_add=True)
class Meta:
verbose_name_plural = _('Ticker')
def __str__(self):
return self.id
串行
class CurrencyTickerSerializer(serializers.HyperlinkedModelSerializer):
currency = serializers.PrimaryKeyRelatedField(many=False, queryset=Currency.objects.all())
class Meta:
model = Ticker
fields = ('currency', 'rank', 'price_dkk', 'market_cap_dkk', 'percent_change_1h', 'percent_change_24h', 'percent_change_7d',)
查看
class CurrencyTickerGetView(ProtectedResourceView):
def get(self, request):
tickers = CurrencyTickerSerializer(Ticker.objects.all(), many=True)
return JsonResponse(tickers.data, safe=False)
答案 0 :(得分:0)
您想使用嵌套关系。 http://www.django-rest-framework.org/api-guide/relations/#nested-relationships
您需要两个序列化程序。一个适合您的货币模型,另一个适用于您的代码..
在您的货币序列化程序中,您需要引用故障单序列化程序。
class CurrencySerializer(serializers.ModelSerializer):
tickers = CurrencyTickerModelSerializer(many=True)
...
在您的视图中获取您要序列化的所有货币,并确保预先填充了您将提前序列化的代码,或者您最终可能会遇到大量查询。