Question

我试图让我的按钮工作。它适用于$_SERVER["REQUEST_METHOD"] == "POST"，但不适用于isset($_POST['submit'])。 $_SERVER["REQUEST_METHOD"] == "POST"的问题在于它为我提供了多个条目。

我的代码：

    if(isset($_POST['submit']))
    {
    $server_address = $_POST['submitServerIp'];
    $server_port = $_POST['submitServerPort'];


    $Query = new SourceQuery( );

    try
    {
        $Query->Connect( $server_address, $server_port, SQ_TIMEOUT, SQ_ENGINE );

        $data = $Query->GetInfo( );
    }
    catch( Exception $e )
    {
        echo $e->getMessage( );
        $error = true;
    }
    $Query->Disconnect( );
if($error == false)
{
    $errorMessage = "false";
    // Create connection
    $conn = mysqli_connect($servername, $username, $password, $dbname);
    // Check connection
    if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

    $stmt = $conn->prepare("INSERT INTO Servers (ipaddress, port) VALUES (?, ?)");
    $stmt->bind_param("ss", $ipaddress, $port);

    $ipaddress = $_POST['submitServerIp'];
    $port = $_POST['submitServerPort'];
    $stmt->execute();

    $stmt->execute();

    $stmt->close();
    mysqli_close($conn);
}
}
?>

HTML：

<form method="post" action="">
<div class="container-fluid search-top">
    <div class="addContainer">
            <div class="addContainer col-sm-12">
                <p class="searchText"><?php echo htmlspecialchars($errorMessage);?></p>
                <div class="container col-md-8 col-md-offset-2 col-sm-10 col-sm-offset-1 col-xs-12 ">
                    <div class="input-group stylish-input-group">
                    <input type="text" name="submitServerIp" class="form-control input-lg" placeholder="Hostname/IP" style="border:0;">
                    <input type="text" name="submitServerPort" class="form-control input-lg" placeholder="Port" style="border:0;">
                        <span class="input-group-addon">
                        <button class="btn btn-primary" type="submit" value="submit">
                            <span class="fas fa-plus" aria-hidden="true"></span>
                        </button>
                        </span>
                    </div>
                </div>
            </div>
    </div>

我可以不按照我使用它的方式使用按钮，还是我做错了什么？

Answer 1

当您使用$_POST[KEY]变量时，该键实际上是您提交的表单元素的name，而不是value。

要解决您的问题，只需在提交按钮中添加name="submit"即可。

<button class="btn btn-primary" type="submit" name="submit" value="submit">
    <span class="fas fa-plus" aria-hidden="true"></span>
</button>

对于数据库中的2个条目，您将调用额外的execute()函数。

    $stmt = $conn->prepare("INSERT INTO Servers (ipaddress, port) VALUES (?, ?)");
    $stmt->bind_param("ss", $ipaddress, $port);

    $ipaddress = $_POST['submitServerIp'];
    $port = $_POST['submitServerPort'];
    $stmt->execute();

    $stmt->execute();

    $stmt->close();
    mysqli_close($conn);

您应该删除上述一行$stmt->execute();。

isset（$ _ POST [＆＃39; submit＆＃39;]）不起作用，但$ _SERVER [＆＃34; REQUEST_METHOD＆＃34;] ==＆＃34; POST＆＃34;不

1 个答案: