在选择构建类型时如何分离构建风格？

Question

我有两个风味维度，分期和测试版。我有两种口味的苹果和香蕉。 Apple和Banana具有应用程序使用的不同manifestHolder值。

我的问题是，当我要选择Build变体时，它结合了两种口味。

即使我已经为他们分配了不同的尺寸。

productFlavors {
    apple {
        dimension "staging"
        applicationIdSuffix ".staging"
        manifestPlaceholders = [onesignal_app_id               : "y",
                                // Project number pulled from dashboard, local value is ignored.
                                onesignal_google_project_number: "REMOTE"]
    }

    banana {
        dimension "beta"
        applicationIdSuffix ".beta"
        manifestPlaceholders = [onesignal_app_id               : "x",
                                // Project number pulled from dashboard, local value is ignored.
                                onesignal_google_project_number: "REMOTE"]
    }
}

Answer 1

由于$(document).ready(function(){ 'use strict'; $('#q').autocomplete({ serviceUrl: "/search/autocomplete/", minChars: 2, dataType: 'json', type: 'GET', formatResult: function (suggestion, currentValue) { return '<a href="'+suggestion.url+'"><li class="list-group-item">'+$.Autocomplete.formatResult(suggestion, currentValue) +'</li></a>'; }, }); }); ，它结合了两者。 你只需要一个维度。

所以假设你有两个dimension：

buildTypes

然后针对buildTypes { debug { debuggable true signingConfig signingConfigs.config } release { debuggable false minifyEnabled false proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro' signingConfig signingConfigs.config } } 执行以下操作：

productFlavors

这将创建4个最终构建变体：

flavorDimensions "default" productFlavors { apple { dimension "default" applicationIdSuffix ".staging" manifestPlaceholders = [onesignal_app_id : "y", // Project number pulled from dashboard, local value is ignored. onesignal_google_project_number: "REMOTE"] } banana { dimension "default" applicationIdSuffix ".beta" manifestPlaceholders = [onesignal_app_id : "x", // Project number pulled from dashboard, local value is ignored. onesignal_google_project_number: "REMOTE"] } }
appleDebug
appleRelease
bananaDebug