使用doctrine插入BDD时symfony出错

时间:2017-12-13 12:36:57

标签: php symfony doctrine-orm orm doctrine

我有一个问题。我不知道它来自哪里。 我是usgin symfony 3.1,我使用Doctrine作为ORM。当我在bdd上请求我没有错误。但是当我想插入时我有这个错误

An exception occurred while executing 'INSERT INTO order (status, part_id, user_id) VALUES (?, ?, ?)' with params [1, "8", "1"]:

对我来说,学说有一个错误,但我没有找到它的起源.......

这是我的控制器动作

    /**
 * @Route("/order/new", name="new_order")
 */
public function newAction(Request $request)
{
    if (false === $this->container->get('security.authorization_checker')->isGranted('ROLE_USER')){
        throw new AccessDeniedException();
    }

    $order = new Order();
    $form = $this->createForm(OrderType::class, $order);
    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        $order->setUser($this->container->get('security.token_storage')->getToken()->getUser());
        $em = $this->getDoctrine()->getManager();
        $em->persist($order);
        $em->flush();
        return $this->redirect($this->generateUrl('homepage'));
    }

    return $this->render('BEBundle:Order:new.html.twig', array(
        'form' => $form->createView(),
    ));

}

这是我的实体

/**

* @ORM \ Table(name =“order”) * @ORM \ Entity(repositoryClass =“BEBundle \ Repository \ OrderRepository”) * / 班级订单 {

CONST ORDER_CREATED = 1;
CONST ORDER_TO_DELIVERY = 3;

/**
* @var integer $id
*
* @ORM\Column(name="id", type="bigint")
* @ORM\Id
* @ORM\GeneratedValue(strategy="IDENTITY")
*/
private $id;

/**
 * @var integer $status
 *
 * @ORM\Column(name="status", type="integer")
 */
private $status;

/**
 * @var Part $part
 *
 * @ORM\ManyToOne(targetEntity="Part", inversedBy="orders")
 * @ORM\JoinColumns({
 *  @ORM\JoinColumn(name="part_id", referencedColumnName="id")
 * })
 */
private $part;

/**
 * @var User $user
 *
 * @ORM\ManyToOne(targetEntity="User", inversedBy="orders")
 * @ORM\JoinColumns({
 *  @ORM\JoinColumn(name="user_id", referencedColumnName="id")
 * })
 */
private $user;

/ ...然后是getter和setter

部分订单

 /**
 * @var ArrayCollection $orders
 *
 * @ORM\OneToMany(targetEntity="Order", mappedBy="part")
 */
private $orders;

用户的订单

    /**
 * @var ArrayCollection $orders
 *
 * @ORM\OneToMany(targetEntity="Order", mappedBy="user")
 */
private $orders;

我不知道为什么会有这个错误。如果有人知道为什么会出现这个错误?

编辑表格类型

class OrderType extends AbstractType

{

/**
 * @param FormBuilderInterface $builder
 * @param array $options
 */
public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('part',EntityType::class , array(
                'class' => Part::class,
                'choice_label' => 'concat',
                'label'     => 'Part to order',
                'error_bubbling' => true,
                'required'  => true,
            )
        )
    ;
}

/**
 * @param OptionsResolver $resolver
 */
public function setDefaultOptions(OptionsResolver $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'BEBundle\Entity\Order',
    ));
}

/**
 * @return string
 */
public function getName()
{
    return 'BEBundle_Order';
}

}

2 个答案:

答案 0 :(得分:2)

ORDER是mysql或doctrine的保留字。这就是为什么插入工作不起作用的原因。被迫用其他名称重命名我的班级订单。现在它正在工作!

答案 1 :(得分:0)

你可以在你的控制器中执行此操作以获得表单无效的原因吗?

 if ($form->isSubmitted() && $form->isValid()) {
        $order->setUser($this->container->get('security.token_storage')->getToken()->getUser());
        $em = $this->getDoctrine()->getManager();
        $em->persist($order);
        $em->flush();
        return $this->redirect($this->generateUrl('homepage'));
    }
else
{
        $formErrors = $form->getErrors(true);        

        $errors = [];

        foreach($formErrors as $key => $error)
        {
           $errors[$key] = $error->getMessageTemplate()."-";
        }

        $fichier = fopen("testFormErrors.txt", "w+");
        fputs($fichier, print_r($errors, true));
        fclose($fichier);

}

//Do what ever you what

所以基本上你应该在testFormErrors.txt文件中得到表单错误 如果它没有帮助,您是否也可以向我们提供您的OrderType类?