Question

我在同一个父目录中有大约100个目录符合命名约定[sitename] .com。我想将它们全部重命名为[sitename] .subdomain.com。

这是我试过的：

for FILE in `ls | sed 's/.com//' | xargs`;mv $FILE.com $FILE.subdomain.com;

但它失败了。有什么想法吗？

Answer 1

使用rename(1)。

rename .com .subdomain.com *.com

如果你有一个perl rename而不是正常的那个，那就行了：

rename s/\\.com$/.subdomain.com/ *.com

Answer 2

使用bash：

for i in *
do
    mv $i ${i%%.com}.subdomain.com
done

$ {i %%。com}结构返回没有'.com'后缀的i的值。

Answer 3

find . -name '*.com' -type d -maxdepth 1 \
| while read site; do
    mv "${site}" "${site%.com}.subdomain.com"
  done

Answer 4

怎么样：

ls |
grep -Fv '.subdomain.com' |
while read FILE; do
  f=`basename "$FILE" .com`
  mv $f.com $f.subdomain.com
done

Answer 5

请参阅：http://blog.ivandemarino.me/2010/09/30/Rename-Subdirectories-in-a-Tree-the-Bash-way

#!/bin/bash
# Simple Bash script to recursively rename Subdirectories in a Tree.
# Author: Ivan De Marino <ivan.demarino@betfair.com>
#
# Usage:
#    rename_subdirs.sh <starting directory> <new dir name> <old dir name>

usage () {
   echo "Simple Bash script to recursively rename Subdirectories in a Tree."
   echo "Author: Ivan De Marino <ivan.demarino@betfair.com>"
   echo
   echo "Usage:"
   echo "   rename_subdirs.sh <starting directory> <old dir name> <new dir name>"

   exit 1
}

[ "$#" -eq 3 ] || usage

recursive()
{
   cd "$1"
   for dir in *
   do
      if [ -d "$dir" ]; then
         echo "Directory found: '$dir'"
         ( recursive "$dir" "$2" "$3" )
         if [ "$dir" == "$2" ]; then
            echo "Renaming '$2' in '$3'"
            mv "$2" "$3"
         fi;
      fi;
   done
}

recursive "$1" "$2" "$3"

Answer 6

试试这个：

for FILE in `ls -d *.com`; do
  FNAME=`echo $FILE | sed 's/\.com//'`;
  `mv $FILE $FNAME.subdomain.com`;
done

需要一个快速的bash脚本

6 个答案: