在Python 2.7中更改字体颜色

时间:2017-12-17 07:05:16

标签: python fonts colors

我创造了一个Pascal的三角形。一切都按我想要的方式运作。我现在想要改变三角形中特定数字的颜色。我希望对角线有不同的颜色,即:计数数字为蓝色,三角形数字为橙色。有没有办法可以改变不同行中数字的颜色,甚至设置一系列颜色(一行中的每个数字都是蓝色,红色,橙色,黄色.....然后以下类似会重新启动顺序,但红色)?

# Pascal's Triangle

def multiplicative(n, k):
    result = 1
    for i in range(1, k+1):
        result = result * (n-(k-i))/i
    return result

def pascal_level(n):
    lists = []
    ns = range(n)
    for n in ns:
        nlist = []
        for k in range(n+1):
            nlist.append(multiplicative(n, k))
        nlist = '     '.join(map(str, nlist))
        lists.append(nlist)
    return lists

def center(strings):
    maxlistlen = len(max(strings, key=len))
    for i, s in enumerate(strings):
        diff = maxlistlen - len(s)
        pad = ' '*(diff/2)
        yield str(i)+'-> '+pad+s

answer = int(raw_input("How many levels do you want? \n"))
ps = pascal_level(answer)
for r in center(ps):
     print r

编辑 - 我对此有一个有限的理解,所以我将不得不玩这些建议。感谢您的帮助,我会在完成后发布更新。我添加了一张类似于我想要创建的图片。Example

2 个答案:

答案 0 :(得分:1)

您可以使用像colored这样的库来更改前景色和背景色,即使在同一行也是如此。

类似的东西:

from colored import stylize, fg

offset = 42  # Starting color
# ...

def pascal_level(n):
    lists = []
    ns = range(n)
    for n in ns:
        nlist = []
        colors = []
        for k in range(n+1):
            nlist.append(multiplicative(n, k))
            color = fg(k + offset) if k + 1 < n//2 else fg(n - k + offset)
            colors.append(color)
        nlist = '     '.join(stylize(str(x), color) for x, color in zip(nlist, colors))
        lists.append(nlist)
    return lists

答案 1 :(得分:1)

此前已经回答过,colorama

Change color of individual print line in Python 3.2? [duplicate]

colorama也适用于2.7

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