c# typemock taking mocked result of last case

Question

I am trying to mock using a method call using typeMock. I have mocked method in different cases but every time I am getting the same result. Following is code:

[TestFixture]
public class HomeControllerSpec
{
    User _fakeUser;
    ProfileSettingsBL _profileSettingBL = null;

    [SetUp]
    public void SetUp()
    {
        // Inital setup
    }


    [TestCase]
    public void DisconnectOutlookCalendarForUserRegisterWithEmail()
    {
        _fakeUser = new User();
        _fakeUser.LoginType = 4; // This is be different in each case

        Isolate.WhenCalled(() => _profileSettingBL.RetrieveUserProfile()).WillReturn(_fakeUser);

        HomeController ctrl = new HomeController();
        var result = ctrl.Disconnect();

        Assert.IsTrue(result.Content);
    }



    [TestCase]
    public void DisconnectOutlookCalendarForUserRegisterWithName()
    {

        _fakeUser = new User();
        _fakeUser.LoginType = 5; // This is be different in each case

        Isolate.WhenCalled(() => _profileSettingBL.RetrieveUserProfile()).WillReturn(_fakeUser);

        HomeController ctrl = new HomeController();
        var result = ctrl.Disconnect();

        Assert.IsTrue(result.Content);
    }

}

When different test case calling Disconnect method of HomeController I am getting _fakeUser.LoginType == 4 always. But when I am removing one of test case both cases running perfectly.

Any Idea?

Answer 1

也许您可以尝试使用class node(object): def __init__(self,value): self.data=value self.left=None self.right=None def insert(Node,value): if Node is None: Node=node(value) else: if value<Node.data: ## if Node.left is None: Node.left=node(value) ## else: insert(Node.left,value) insert(Node.left,value) else: ## if Node.left is None: Node.left=node(value) ## else: insert(Node.left,value) insert(Node.right,value) 属性？ 它指示Typemock Isolator在测试完成后清理测试结果。