Question

我有一个类似..

的sql语句

Select
Res1,
Res2,
Res3,
Res4
from tbl1
where Res1=1
Group by Res2
Having Res4>0

我想要最后一栏，但该栏目基于Res1和Res3。个人陈述将是

Select
Res5
from tbl1
where Res1=1 and max(Res3)
Group by Res2
Having Res4>0

我想将Res5合并到第一个语句中。

Res3是执行第一个语句可以获得的总值。

我想做..

Select
Res1,
Res2,
Res3,
Res4
(Select
Res5
from tbl1
where Res1=1 and max(Res3)
Group by Res2
Having Res4>0)
from tbl1
where Res1=1
Group by Res2
Having Res4>0

但显然这是不正确的。

如何实现？

确切的代码是

declare @noshow int, @target int; 
set @noshow=20;
set @target=1200;

select
CONVERT(VARCHAR(10), visit.regdate, 103) as 'Date',
datename(weekday, visit.regdate) as 'Day',
count(queueno) as 'Total_Served',
sum(case when datediff(second, starttime, nexttime)<= @target then 1 else 0 end) as 'Less_Target',
isnull((sum(case when datediff(second, starttime, nexttime)<= @target then 1 else 0 end)*100)/count(queueno),0) as 'Less_Target_Per',
sum(case when datediff(second, starttime, nexttime)> @target then 1 else 0 end) as 'More_Target',
isnull((sum(case when datediff(second, starttime, nexttime)> @target then 1 else 0 end)*100)/count(queueno),0) as 'More_Target_Per',
isnull(CONVERT(varchar(6), avg(datediff(second,nexttime,endtime))/3600)+ ':' + RIGHT('0' + CONVERT(varchar(2), (sum(datediff(second,nexttime,endtime)) % 3600) / 60), 2)+ ':' + RIGHT('0' + CONVERT(varchar(2), sum(datediff(second,nexttime,endtime)) % 60), 2),0) as 'Avg_Serving_Time',
isnull(CONVERT(varchar(6), max(datediff(second,starttime,nexttime))/3600)+ ':' + RIGHT('0' + CONVERT(varchar(2), (max(datediff(second,starttime,nexttime)) % 3600) / 60), 2)+ ':' + RIGHT('0' + CONVERT(varchar(2), max(datediff(second,starttime,nexttime)) % 60), 2),0) as 'Max_Waiting_Time',
CONVERT(VARCHAR(26), getdate(), 108) as 'Cus_Arrival'
from visit 
where visit.branchno in (  '1007'    )  and  visit.wstation in ('1'  ,'10'  ,'11'  ,'15'  ,'2'  ,'20'  ,'21'  ,'23'  ,'24'  ,'28'  ,'29'  ,'3'  ,'30'  ,'31'  ,'32'  ,'33'  ,'4'  ,'5'  ,'6'  ,'7'  ,'8'  ,'9'    )  and visit.catname in ('BY PASS'  ,'REG STORE'  ,'REGISTRATION'  ,'ROOM 1 to 4'  ,'ROOM A1 & A2'  ,'ROOM A3 & A4'  ,'ROOM A5-A7&A9-A11'  ,'ROOM A8-BMD'  ,'ROOM B20'  ,'ROOM B21 B23 B24'  ,'Ward Cases'    )  and visit.btnname in ('BY PASS'  ,'REG STORE'  ,'REGISTRATION'  ,'ROOM 1 to 4'  ,'ROOM A1 & A2'  ,'ROOM A3 & A4'  ,'ROOM A5-A7&A9-A11'  ,'ROOM A8-BMD'  ,'ROOM B20'  ,'ROOM B21'  ,'B23'  ,'B24'  ,'Ward Cases'  )   and (CONVERT(VARCHAR(10), visit.tmstamp, 111) in(  '2010/11/01'     ,'2010/11/02'     ,'2010/11/03'     ,'2010/11/04'     ,'2010/11/05'     ,'2010/11/06'     ,'2010/11/07'     ,'2010/11/08'     ,'2010/11/09'     ,'2010/11/10'     ,'2010/11/11'     ,'2010/11/12'     ,'2010/11/13'     ,'2010/11/14'     ,'2010/11/15'     ,'2010/11/16'     ,'2010/11/17'     ,'2010/11/18'     ,'2010/11/19'     ,'2010/11/20'     ,'2010/11/21'     ,'2010/11/22'     ,'2010/11/23'     ,'2010/11/24'     ,'2010/11/25'     ,'2010/11/26'     ,'2010/11/27'     ,'2010/11/28'     ,'2010/11/29'     ,'2010/11/30'     ,'2010/12/01'     ,'2010/12/02'     ,'2010/12/03'     ,'2010/12/04'     ,'2010/12/05'     ,'2010/12/06'     ,'2010/12/07'     ,'2010/12/08'     ,'2010/12/09'     ,'2010/12/10'     ,'2010/12/11'     ,'2010/12/12'     ,'2010/12/13'     ,'2010/12/14'     ,'2010/12/15'     ,'2010/12/16'     ,'2010/12/17'     ,'2010/12/18'     ,'2010/12/19'     ,'2010/12/20'     ,'2010/12/21'     ,'2010/12/22'     ,'2010/12/23'     ,'2010/12/24'     ,'2010/12/25'     ,'2010/12/26'     ,'2010/12/27'     ,'2010/12/28'     ,'2010/12/29'     ,'2010/12/30'     ,'2010/12/31' )) and  datediff(second,nexttime,endtime)>@noshow 
group by regdate
having sum(case when datediff(second, starttime, nexttime)> @target then 1 else 0 end) >0

忽略where子句。太长了。

我想用第二个陈述替换Cus_Arrival。

Max_Waiting_Time实际上是到达时间。

Answer 1

我假设您使用的是MS SQL Server。

Select
    Res1,
    Res2,
    Res3,
    Res4
from tbl1
where Res1=1
Group by Res2
Having Res4>0

无效。

您无法选择不属于该组的列。

在此处阅读有关群组的信息 http://msdn.microsoft.com/en-us/library/ms177673.aspx

任何表中的每个表或视图列非聚集表达式列表必须包含在 GROUP BY列表：

有没有办法实现以下代码？

1 个答案: