MID RID Name IsVisible
100 1 AA 1
100 2 AA 0
101 1 BB 1
101 2 BB 1
102 1 CC 0
102 2 CC 0
103 1 DD 0
103 2 DD 1
如何在所有RID中选择IsVisible = 0的不同MID。
预期结果为102，对于所有RID，IsVisible = 0。
答案 0 :(得分：0)
使用class Trie:
def __init__(self):
self.word_end = '_end_'
self.root = {}
def add_word(self, word):
self.add_words([word])
def add_words(self, words):
for word in words:
current_dict = self.root
for letter in word:
current_dict = current_dict.setdefault(letter, {})
current_dict[self.word_end] = self.word_end
def check_word(self, word):
current_dict = self.root
for letter in word:
if letter in current_dict:
current_dict = current_dict[letter]
else:
return False
else:
if self.word_end in current_dict:
return True
else:
return False
tree = Trie()
tree.add_words(['foo', 'bar', 'baz', 'barz'])
print tree
"""
{'b': {'a': {'r': {'_end_': '_end_', 'z': {'_end_': '_end_'}},
'z': {'_end_': '_end_'}}},
'f': {'o': {'o': {'_end_': '_end_'}}}}
"""
print check_word('baz')
# True
print check_word('barz')
# True
print check_worf('barzz')
# False
NOT EXISTS答案 1 :(得分：0)
这个问题有点不清楚，但也许这就是你想要的......？
执行GROUP BY，检查max和min IsVisible = 0。
select MID
from tablename
group by MID
having max(cast(IsVisible as int)) = 0