将XML响应转换为.CSV文件

时间:2011-01-25 11:29:55

标签: c# xml web-services csv

我有以下代码,

我正在向Web服务发送一组数据,来自Web服务的响应当前显示在Web表单中,如下所示。

private void Form1_Load(object sender, EventArgs e)
    {
        int ASent;
        int CSent;
        webservice.Results returned = convert();
        txtResult.Text = System.Convert.ToString(returned.status);
        txtMoreRes1.Text = returned.errorDetails[0].errorDetails;
        txtMoreRes2.Text = returned.errorDetails[1].errorDetails;
        txtMoreRes3.Text = returned.errorDetails[2].errorDetails;
        txtMoreRes4.Text = returned.errorDetails[3].errorDetails;
        date.Text = System.Convert.ToString(DateTime.Today);
        time.Text = System.Convert.ToString(DateTime.Now.TimeOfDay);
                }

我现在需要的是将'返回'的结果从xml响应转换为.csv文件。然后让代码将.csv保存到C盘上的某个位置。如何更改我的代码才能执行此操作?

感谢您的时间!

3 个答案:

答案 0 :(得分:0)

 StringBuilder SbCSV = new StringBuilder();
            int ActualSent;
            int CommitmentSent;
            webservice.summaryResults returned = convert(out ActualSent, out CommitmentSent);
            //txtResult.Text = System.Convert.ToString(returned.status);
            SbCSV.Append(System.Convert.ToString(returned.status));
            //txtMoreRes1.Text = returned.errorDetails[0].errorDetails;
            SbCSV.Append("," + returned.errorDetails[0].errorDetails);
            //txtMoreRes2.Text = returned.errorDetails[1].errorDetails;
            SbCSV.Append("," + returned.errorDetails[1].errorDetails);
            // Similary ...
            txtMoreRes3.Text = returned.errorDetails[2].errorDetails;
            txtMoreRes4.Text = returned.errorDetails[3].errorDetails;
            actualSum.Text = System.Convert.ToString(returned.actualSum);
            commitmentSum.Text = System.Convert.ToString(returned.commitmentSum);
            date.Text = System.Convert.ToString(DateTime.Today);
            time.Text = System.Convert.ToString(DateTime.Now.TimeOfDay);
            actualsumsent.Text = ActualSent.ToString();
            commitmentsumsent.Text = CommitmentSent.ToString();
            errorposition1.Text = System.Convert.ToString(returned.errorDetails[0].errorPosition);
            errorposition2.Text = System.Convert.ToString(returned.errorDetails[1].errorPosition);
            errorposition3.Text = System.Convert.ToString(returned.errorDetails[2].errorPosition);
            errorposition4.Text = System.Convert.ToString(returned.errorDetails[3].errorPosition);

            TextWriter Tw = new StreamWriter("Your_FilePath_Name.csv");
            Tw.Write(SbCSV.ToString());
            Tw.Close();
            Tw.Dispose();

答案 1 :(得分:0)

您也可以使用FileHelpers来完成这些工作。 您必须创建一个名为MyClass的类,其属性与.csv格式匹配(每列=一个属性) 您使用FileHelper构建此类对象的List并以这种方式转换为csv:

FileHelperEngine engine = new FileHelperEngine(typeof(MyClass));

MyClass[] res = null; //Fill your array here from your code.

// To Write Use:
engine.WriteFile("FileOut.txt", res);

答案 2 :(得分:0)

您也可以使用XML Transformation

执行此操作