删除重复代码调试

时间:2017-12-23 13:49:24

标签: python python-3.x

作为一名新手python程序员,我一直在做一些练习,但我不明白为什么这段代码对我不起作用。

现在我的练习是:

  

定义并测试名为removeDuplicates(somelist)的函数,该函数从给定列表中删除所有重复项,并在保持原始顺序的同时将其余元素作为列表返回。还定义一个main()函数,该函数调用给定命令行参数的removeDuplicates函数并打印结果列表。

到目前为止,这是我的代码:

import sys

def main():
    userInput = int(input(""))
    removeDuplicates(somelist)
    print (unique)

def removeDuplicates(userInput):
    duplicate = set()
    unique = []   
    for x in userInput:
        if x not in duplicate:
            unique.append(x)
            duplicate.add(x)

    print (unique)

def removeDuplicates(somelist):
    duplicate = set()
    unique = [] 
    for line in sys.stdin:
        line = line.rstrip()
        if x not in sys.stdin:
            unique.append(x)
            duplicate.add(x)

    return unique

if __name__ =='__main__':
    main()

无论我做什么,我都会收到错误代码。此代码的错误代码为:

Traceback (most recent call last):
File "removeDuplicates.py", line 31, in <module>
main()
File "removeDuplicates.py", line 5, in main
removeDuplicates(somelist)
NameError: name 'somelist' is not defined`

2 个答案:

答案 0 :(得分:1)

您未被声明为somelist,可能是这样,

......
userInput = int(input(""))
removeDuplicates(userInput)
......

答案 1 :(得分:0)

此代码只打印唯一值列表:

def main():
    userInput = input("Enter an integers, separated by spaces(' '):").split()
    unique = removeDuplicates(userInput)
    print(unique)

def removeDuplicates(userInput):
    unique = []
    for i in userInput:
        if i not in unique:
            unique.append(i)
    return unique

if __name__ =='__main__':
    main()

希望它有所帮助!

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