Question

我正在使用以下代码：

def mailme():
    print('connecting')
    server = smtplib.SMTP('mail.server.com', 26)
    server.connect("mail.server.com", 465)
    print('connected..')
    server.ehlo()
    server.starttls()
    server.ehlo()
    server.login('scraper@server.com', "pwd")
    text = 'TEST 123'
    server.sendmail('me@sserver.com', 'me@server2.com', text)
    server.quit()

但它给出了错误：

raise SMTPServerDisconnected("Connection unexpectedly closed")
smtplib.SMTPServerDisconnected: Connection unexpectedly closed

通过Telnet连接时，它可以工作：

~ telnet mail.zoo00ooz.com 26
Trying 1.2.3.4...
Connected to server.com.
Escape character is '^]'.
220-sh97.surpasshosting.com ESMTP Exim 4.87 #1 Mon, 01 Jan 2018 00:23:02 -0500 
220-We do not authorize the use of this system to transport unsolicited, 
220 and/or bulk e-mail.
^C^C

Answer 1

您无需连接两次！正如documentation所说：

异常smtplib.SMTPServerDisconnected¶

当服务器意外断开连接，或者在将SMTP实例连接到服务器之前尝试使用SMTP实例时，会引发此异常。

您的代码应该更像这样（即使它有点过于复杂，请参阅示例代码的文档）

def mailme():
    SERVER_NAME='mail.whatever.com'
    SERVER_PORT=25
    USER_NAME='user'
    PASSWORD='password'
    print('connecting')
    server = smtplib.SMTP(SERVER_NAME, SERVER_PORT)
    print('connected..')
    server.ehlo()
    server.starttls()
    server.ehlo()
    server.login(USER_NAME, PASSWORD)
    text = 'TEST 123'
    server.sendmail('whoever@whatever.com', 'another@hatever.com', text)
    server.quit()

mailme()

Answer 2

我已使用下面的Python 3.6.0附加了示例邮件代码

import smtplib as sl
server = sl.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.ehlo()
server.login('sender_mail_id@gmail.com','sender_password')
server.sendmail('sender_mail_id@gmail.com',['first_receiver_mail_id@gmail.com','second_receiver_mail_id@gmail.com','and_so_on@gmail.com'],'data')

Smtplib：连接意外关闭

2 个答案: