Question

我对Laravel相当新，并希望创建一个功能，我将通过单击链接从数据库中删除单个记录。

以下是视图中的代码：

@foreach($companies as $company)
     <tr>
         <td><a href="/companies/{{$company->id}}"> {{$company->name}}</a></td>
         <td><a href="/companies/{{$company->id}}"> {{$company->descriptions}}</a></td>
         <td><a href="/companies/{{$company->id}}"> {{$company->comptype->name}}</a></td>
         <td>

              <a href="{{route('companies.edit', $company->id)}}" class="btn btn-xs btn-default"><i class="fa fa-edit"></i></a>

               <a onclick="
                     var result = confirm('Are you sure you wish to delete this Company?');
       if( result ){ 
    event.preventDefault();
                                                                      document.getElementById('delete-form').submit();
                       }
                                                                  "
                                                   class="btn btn-xs btn-default"><i class="fa fa-trash"></i> </a>

                 <form id="delete-form" action="{{ route('companies.destroy',[$company->id]) }}"
                                                      method="POST" style="display: none;">
                                                    <input type="hidden" name="_method" value="delete">
                                                    {{ csrf_field() }}

                 </form>

                                            </td>
                                        </tr>
@endforeach

接下来是Controller中的destroy方法

public function destroy(Company $company)
{
    //
   // dd($company);
    $findCompany = Company::findOrFail( $company->id);


    if($findCompany->delete()){

        //redirect
        return redirect()->route('companies.index')
            ->with('success' , 'Company deleted successfully');
    }

    return back()->withInput()->with('error' , 'Company could not be deleted');
}

表单如下所示：

当点击垃圾箱，删除特定记录时，表上的记录会被删除，我尝试删除的内容并不重要，第一条记录总是会被删除。当我做了一个死机时，我发现URL有正确的记录，但是dd显示第一条记录将被删除。我是Laravel的新手，我使用Laravelcollective / html完成了这项工作，但不幸的是它与Laravel 5.5.28不兼容。请帮助

Answer 1

问题出在JS代码中。您的JS代码总是相同的删除形式。要解决此问题，您需要使用唯一ID：

<form id="delete-form{{ $company->id }}"

然后：

document.getElementById('delete-form{{ $company->id }}').submit();

此外，混合JS和PHP是一种不好的做法。你应该把所有的JS放到一个单独的JS文件中。

Answer 2

试试这是我的项目代码：

查看文件：

<td>
<form action="{{action('TagController@destroy', $row['id'])}}" method="post">
{{csrf_field()}}
<input name="_method" type="hidden" value="DELETE">
<button class="btn btn-danger" type="submit">Delete</button>
</form>
</td>

TagController.php：

public function destroy($id)
    {   


        $tags = Tag::find($id);
         $success = $tags->delete();

            if($success)
            {
                return redirect('/admin/tag')
                ->with('success','Tag deleted.');
            }

        return back()->withInput()->with('errors','Some error...');
    }

Answer 3

试试这个请参阅表单操作"{{ route('companies.destroy',[$company->id]) }}"至{{ url('companies/destroy/'.$company->id) }}
看到毁灭方法错了点击link

完美方法

public function destroy($id){
$findCompany = Company::findOrFail($id);
if($findCompany->delete()){
    //redirect
    return redirect()->route('companies.index')
        ->with('success' , 'Company deleted successfully');
}
return back()->withInput()->with('error' , 'Company could not be deleted');}

Answer 4

尝试使用此代码查看视图文件：

 <div class="col-xs-12">
<a href="{{url('/delete')}}/{{$allDemos[$i]->id}}"  class='btndelete'>
     <i class="fa fa-trash"></i>
</a>

SliderControler.php：

 public function delete($id){
      $Slider = Slider::find($id); 
      unlink('slider_images/'.$Slider->slider_img);   
      $Slider->delete();
      return redirect('/slider');
 }

Answer 5

试试这个：

public function destroy(Company $company)
{ 
    if($company->delete()){
        //redirect
        return redirect()->route('companies.index')
            ->with('success' , 'Company deleted successfully');
    }

    return back()->withInput()->with('error' , 'Company could not be deleted');
}

删除单个记录Laravel

5 个答案: