Question

我必须遍历多个文件夹，最后检查最终文件夹中是否有三个文件夹。如果文件夹中存在三个文件夹，则不执行任何操作，否则打印文件夹路径或名称。我发现很难使其工作，欢迎任何建议，提前致谢

这就是我现在所拥有的，

check_empty =['One','Two','Three']
path = '/mnt/sdc1/Username/'
folders = next(os.walk('/mnt/sdc1/Mahajan/'))[1]
for folder in folders:
    files_in_folders = os.listdir(path +folder)
    for files_in in files_in_folders:
        for files in os.listdir(path+folder+'/'+files_in):
            for items in check_empty:
               if files in check_empty:
                    print(folder +'Good')
               else:
                    print(folder+'NotGood')

Answer 1

os.walk已经为您提供了获取文件夹中所有文件的功能：

check_empty = set(check_empty)  # set is faster for simple check in unique items
for root, dirs, files in os.walk('/mnt/sdc1/Mahajan/'):
    for file in files:
        filename = os.path.basename(file)
        if filename in check_empty:
            print(root + 'Good')
        else:
            print(root + 'NotGood')

循环通过许多文件夹

1 个答案: