如何使用JavaScript在列报告ID中创建多值选择？

Question

SQL查询 -

select REPORT_ID,CASE_NUM,REPORT_DUE_DATE,REPORT_SUBMISSTION_DATE,REPORT_SUBMISSION_USER_ID
from CLINICALDW.ESM_TABLE 
Where REPORT_ID In (?)

JavaScript -

this.queryText =
this.queryText.replace("100415",params["ReportId"].value.join(" "));

Answer 1

enter image description here

使用此java脚本代码并将Lov Driver作为数字