在Django admin

时间:2018-01-08 07:36:18

标签: python json django

我有一个Django模型如下:

class BodyHeight(models.Model):
    seats = models.ForeignKey(to=Seats)
    name = models.CharField(max_length=127, null=True, blank=True)
    key = models.CharField(max_length=100, null=True)
    data = models.TextField(null=True, blank=True)

    class Meta:
        verbose_name_plural = "Body heights"

    def __str__(self):
        return self.name

在数据字段中,我存储了json数据,如下所示:

{"url": "https://some_url=/BE?category=COMMERCIAL, "images": ["url_to_some_image"]}

我想在Django管理面板中只显示该字段的网址。

现在我有:

class BodyHeightAdmin(admin.ModelAdmin):
    search_fields = ('name', )
    list_display = ('id', 'name', 'key', )
    list_display_links = ('id', 'name', 'key', )

admin.site.register(BodyHeight, BodyHeightAdmin)

没有数据字段。如果我在data中添加list_display字段而不是整个json(丑陋格式),但我只想要url

知道怎么做吗?

4 个答案:

答案 0 :(得分:2)

我在Django Admin中为JSONField添加基本格式的解决方案:

import json
import logging

from django.contrib import admin
from django.contrib.postgres.fields import JSONField
from django.forms import widgets


logger = logging.getLogger(__name__)


class PrettyJSONWidget(widgets.Textarea):

    def format_value(self, value):
        try:
            value = json.dumps(json.loads(value), indent=2, sort_keys=True)
            # these lines will try to adjust size of TextArea to fit to content
            row_lengths = [len(r) for r in value.split('\n')]
            self.attrs['rows'] = min(max(len(row_lengths) + 2, 10), 30)
            self.attrs['cols'] = min(max(max(row_lengths) + 2, 40), 120)
            return value
        except Exception as e:
            logger.warning("Error while formatting JSON: {}".format(e))
            return super(PrettyJSONWidget, self).format_value(value)


class JsonAdmin(admin.ModelAdmin):
    formfield_overrides = {
        JSONField: {'widget': PrettyJSONWidget}
    }

用法:

admin.site.register(models.MyModel, JsonAdmin)

希望它将对您有帮助!

答案 1 :(得分:1)

我更改了bodyHeightAdmin类,如下所示:

class BodyHeightAdmin(admin.ModelAdmin):
    search_fields = ('name', )
    list_display = ('id', 'name', 'key', 'url', )
    list_display_links = ('id', 'name', 'key', )

    def url(self, instance):
        data = json.loads(instance.data)
        return data["url"]

它有效。

答案 2 :(得分:1)

在这种情况下,将JSONField设置为只读

# set 'url' editable=False in model defintion

class BodyHeightAdmin(admin.ModelAdmin):
    search_fields = ('name', )
    list_display = ('id', 'name', 'key', 'get_pprint_url', )
    list_display_links = ('id', 'name', 'key', )
    readonly_fields = ('get_pprint_url', )

    def url(self, instance):
        data = json.loads(instance.data)
        return data["url"]

    actions = [
        'process_webhook_events',
        'reset_webhook_events'
    ]

    def get_pprint_url(self, obj=None):
        result = ''
        if obj and obj.url:
            result = json.dumps(obj.url, indent=4, sort_keys=True)
            # keep spaces
            result_str = f'<pre>{result}</pre>'
            result = mark_safe(result_str)
        return result
    get_pprint_url.short_description = 'url'

答案 3 :(得分:0)

要在管理页面中显示格式化的JSON,我建议您使用python库django-json-widget。它易于使用且功能强大(您可以编辑格式化的JSON)。

1)安装库pip install django-json-widget

2)将django-json-widget添加到settings.py中的installed_apps

INSTALLED_APPS = (
    ...
    'django_json_widget',
    ...
)

3)将以下代码添加到admin.py中(不要忘记用真实的模型名称更改YourModel)

from django.contrib import admin
from django.contrib.postgres import fields
from django_json_widget.widgets import JSONEditorWidget
from .models import YourModel


@admin.register(YourModel)
class YourModelAdmin(admin.ModelAdmin):
    formfield_overrides = {
        fields.JSONField: {'widget': JSONEditorWidget},
    }