Question

我希望合并2个列表列表。在第一段代码中，我可以合并2个没有重复元素的字符串列表！这就是我要找的东西，但有2个列表（字符串）：

list1 = ['a', 'b', 'c', 'd']
list2 = ['c', 'd', 'e', 'f']
# List merge without dupe
list1.extend([element for element in list2 if element not in list1])
print list1
>>>
['a', 'b', 'c', 'd', 'e', 'f']

我在寻找什么：

list1=[["artur","1/1/2018","0.5"],
       ["paco","1/1/2018","2.11"],
       ["pepe","1/1/2018","11.2"],
       ["artur","2/1/2018","0.5"],
       ["paco","2/1/2018","2.11"],
       ["pepe","2/1/2018","11.2"]]

list2=[["artur","1/1/2018","Estable"],
       ["paco","1/1/2018","Critico"],
       ["pepe","1/1/2018","Critico"], 
       ["artur","2/1/2018","Estable"],
       ["paco","2/1/2018","Critico"],
       ["pepe","2/1/2018","Critico"]]

#desired output:
>>>list1
[["artur","1/1/2018","0.5","Estable"],
 ["paco","1/1/2018","2.11","Critico"],
 ["pepe","1/1/2018","11.2","Critico"],
 ["artur","2/1/2018","0.5","Estable"],
 ["paco","2/1/2018","2.11","Critico"],
 ["pepe","2/1/2018","11.2","Critico"]]

版：

如果我的列表是：

list1=[["artur,1/1/2018,0.5"],
       ["paco,1/1/2018,2.11"],
       ["pepe,1/1/2018,11.2"],
       ["artur,2/1/2018,0.5"],
       ["paco,2/1/2018,2.11"],
       ["pepe,2/1/2018,11.2"]]

list2=[["artur,1/1/2018,Estable"],
       ["paco,1/1/2018,Critico"],
       ["pepe,1/1/2018,Critico"], 
       ["artur,2/1/2018,Estable"],
       ["paco,2/1/2018,Critico"],
       ["pepe,2/1/2018,Critico"]]

我必须将csv转换为列表，但我有这样的列表，而不是我在问题的第一行中提出的问题！

Answer 1

一个嵌套的for循环检查每个子列表的前两个元素，并在找到匹配时附加：

for sub1 in list1:
    for sub2 in list2:
        if sub1[:2] == sub2[:2]:
            sub1.append(sub2[-1])
            continue

输出：

>>>list1
[['artur', '1/1/2018', '0.5', 'Estable'],
 ['paco', '1/1/2018', '2.11', 'Critico'],
 ['pepe', '1/1/2018', '11.2', 'Critico'],
 ['artur', '2/1/2018', '0.5', 'Estable'],
 ['paco', '2/1/2018', '2.11', 'Critico'],
 ['pepe', '2/1/2018', '11.2', 'Critico']]

Answer 2

您可以使用for

进行enumerate()循环

list1=[["artur","1/1/2018","0.5"],
       ["paco","1/1/2018","2.11"],
       ["pepe","1/1/2018","11.2"],
       ["artur","2/1/2018","0.5"],
       ["paco","2/1/2018","2.11"],
       ["pepe","2/1/2018","11.2"]]

list2=[["artur","1/1/2018","Estable"],
       ["paco","1/1/2018","Critico"],
       ["pepe","1/1/2018","Critico"], 
       ["artur","2/1/2018","Estable"],
       ["paco","2/1/2018","Critico"],
       ["pepe","2/1/2018","Critico"]]


for i, item in enumerate(list2):
    list1[i].append(item[-1])

>>> pprint(list1)
[['artur', '1/1/2018', '0.5', 'Estable'],
 ['paco', '1/1/2018', '2.11', 'Critico'],
 ['pepe', '1/1/2018', '11.2', 'Critico'],
 ['artur', '2/1/2018', '0.5', 'Estable'],
 ['paco', '2/1/2018', '2.11', 'Critico'],
 ['pepe', '2/1/2018', '11.2', 'Critico']]

修改：

list1=[["artur,1/1/2018,0.5"], ["paco,1/1/2018,2.11"], ["pepe,1/1/2018,11.2"], ["artur,2/1/2018,0.5"], ["paco,2/1/2018,2.11"], ["pepe,2/1/2018,11.2"]] list2=[["artur,1/1/2018,Estable"], ["paco,1/1/2018,Critico"], ["pepe,1/1/2018,Critico"], ["artur,2/1/2018,Estable"], ["paco,2/1/2018,Critico"], ["pepe,2/1/2018,Critico"]] # slice assignment list1[:] = [''.join(item).split(',') for item in list1] list2[:] = [''.join(item).split(',') for item in list2] for i, item in enumerate(list2): list1[i].append(item[-1]) >>> pprint(list1) [['artur', '1/1/2018', '0.5', 'Estable'], ['paco', '1/1/2018', '2.11', 'Critico'], ['pepe', '1/1/2018', '11.2', 'Critico'], ['artur', '2/1/2018', '0.5', 'Estable'], ['paco', '2/1/2018', '2.11', 'Critico'], ['pepe', '2/1/2018', '11.2', 'Critico']]

Answer 3

尝试：

ziplist = list(zip(list1, list2))
outlist = []
for z in ziplist:
    for i in z[1]:
        if i not in z[0]:
            z[0].append(i)
    outlist.append(z[0])

print(outlist)

输出：

[['artur', '1/1/2018', '0.5', 'Estable'], 
 ['paco', '1/1/2018', '2.11', 'Critico'], 
 ['pepe', '1/1/2018', '11.2', 'Critico'], 
 ['artur', '2/1/2018', '0.5', 'Estable'], 
 ['paco', '2/1/2018', '2.11', 'Critico'], 
 ['pepe', '2/1/2018', '11.2', 'Critico']]

合并2个列表列表

3 个答案: