我的表格包含每天的销售数据，如下所示：
Date ItemNo quantity
-------------------------------------
2017-11-25 123 2
2017-11-25 326 4
2017-11-26 123 . 3
2017-11-27 123 1
2017-11-28 123 5
2017-11-28 . 326 . 1
2017-11-29 . 123 9
2017-11-30 . 123 7
我只限制了2个项目，现在使用此表我想构建每周聚合表，如下所示。不要担心周列，我有另一个逻辑来获得该列：
每周聚合表：
Week Item Total Quantity Sat Sun Mon Wed Tue Thu Fri
4 123 27 3 1 . 5 9 . 7 0 2
答案 0 :(得分：1)
使用CASE计算带有聚合（最大或最小）的Day列，以获得每个项目的单行：
((JavascriptExecutor) driver).executeScript("window.open('http://localhost:8080/games.html#machine');");
如果每个日期可以有多个记录，则您需要对其进行汇总，然后使用 select
Item,
max(total_quantity) total_quantity,
max(case when date_format(your_date,'EEE') = 'Sat' then quantity end) Sat,
max(case when date_format(your_date,'EEE') = 'Sun' then quantity end) Sun,
max(case when date_format(your_date,'EEE') = 'Mon' then quantity end) Mon,
max(case when date_format(your_date,'EEE') = 'Wed' then quantity end) Wed,
max(case when date_format(your_date,'EEE') = 'Tue' then quantity end) Tue,
max(case when date_format(your_date,'EEE') = 'Thu' then quantity end) Thu,
max(case when date_format(your_date,'EEE') = 'Fri' then quantity end) Fri
from (--subquery for calculating total_quantity by Item
select s.*,
sum(quantity) over(partition by Item) total_quantity
from sales_data
)s
group by Item;
代替sum()作为日期列。
答案 1 :(得分：0)
这是另一种方法
select * from d1;
+-------------+----------+---------+--+
| d1.bdate | d1.item | d1.qty |
+-------------+----------+---------+--+
| 2017-11-25 | 123 | 2 |
| 2017-11-25 | 123 | 2 |
| 2017-11-25 | 326 | 4 |
| 2017-11-26 | 123 | 3 |
| 2017-11-27 | 123 | 1 |
| 2017-11-28 | 123 | 5 |
| 2017-11-28 | 326 | 1 |
| 2017-11-29 | 123 | 9 |
| 2017-11-30 | 123 | 7 |
+-------------+----------+---------+--+
select weekofyear(bdate) as week, sum(qty) as total,
item, from_unixtime(unix_timestamp(bdate,'yyyy-MM-dd'),'EEE') as wday,
map(from_unixtime(unix_timestamp(bdate,'yyyy-MM-dd'),'EEE'), sum(qty)) as gmap
from d1
group by weekofyear(bdate), item,
from_unixtime(unix_timestamp(bdate,'yyyy-MM-dd'),'EEE')
+-------+--------+-------+-------+------------+--+
| week | total | item | wday | gmap |
+-------+--------+-------+-------+------------+--+
| 47 | 4 | 123 | Sat | {"Sat":4} |
| 47 | 3 | 123 | Sun | {"Sun":3} |
| 47 | 4 | 326 | Sat | {"Sat":4} |
| 48 | 1 | 123 | Mon | {"Mon":1} |
| 48 | 7 | 123 | Thu | {"Thu":7} |
| 48 | 5 | 123 | Tue | {"Tue":5} |
| 48 | 9 | 123 | Wed | {"Wed":9} |
| 48 | 1 | 326 | Tue | {"Tue":1} |
+-------+--------+-------+-------+------------+--+
select week, item, sum(total) as totals,
collect_list(s.gmap['Sun']) as Sun,
collect_list(s.gmap['Mon']) as Mon,
collect_list(s.gmap['Tue']) as Tue,
collect_list(s.gmap['Wed']) as Wed,
collect_list(s.gmap['Thu']) as Thu,
collect_list(s.gmap['Fri']) as Fri,
collect_list(s.gmap['Sat']) as Sat
from
(select weekofyear(bdate) as week, sum(qty) as total,
item, from_unixtime(unix_timestamp(bdate,'yyyy-MM-dd'),'EEE') as wday,
map(from_unixtime(unix_timestamp(bdate,'yyyy-MM-dd'),'EEE'), sum(qty)) as gmap
from d1
group by weekofyear(bdate), item, from_unixtime(unix_timestamp(bdate,'yyyy-MM-dd'),'EEE')
) s
group by week, item
+-------+-------+---------+------+------+------+------+------+------+------+--+
| week | item | totals | sun | mon | tue | wed | thu | fri | sat |
+-------+-------+---------+------+------+------+------+------+------+------+--+
| 47 | 123 | 7 | [3] | [] | [] | [] | [] | [] | [4] |
| 47 | 326 | 4 | [] | [] | [] | [] | [] | [] | [4] |
| 48 | 123 | 22 | [] | [1] | [5] | [9] | [7] | [] | [] |
| 48 | 326 | 1 | [] | [] | [1] | [] | [] | [] | [] |
+-------+-------+---------+------+------+------+------+------+------+------+--+