Question

这是我想要做的......

执行一系列任务。每个任务需要在x秒内完成。如果没有完成，请记录超时并继续处理下一次发射。

public static void main(String[] args) {
    Observable<String> source = Observable.create(emitter -> {
        emitter.onNext(task(0, "A"));
        emitter.onNext(task(2, "B")); // this one times out
        emitter.onNext(task(0, "C"));
        emitter.onNext(task(0, "D"));
        emitter.onComplete();
        });

    source.subscribeOn(Schedulers.computation())
          .timeout(1, TimeUnit.SECONDS, Observable.just("timeout"))
          .blockingSubscribe(s -> System.out.println("RECEIVED: " + s));
}

private static String task(int i, String string) {
    try {
        TimeUnit.SECONDS.sleep(i);
    }
    catch (InterruptedException e) {

    }

    return string;

}

实际结果

收到：A RECEIVED：超时

预期结果

收到：A   收到：超时
  收到：C
  收到：D

基本上我不希望排放在超时时终止。

Answer 1

您可以推迟执行任务并分别应用timeout：

Observable<String> source = Observable.create(
        (ObservableEmitter<Callable<String>> emitter) -> {
    emitter.onNext(() -> task(0, "A"));
    emitter.onNext(() -> task(2, "B")); // this one times out
    emitter.onNext(() -> task(0, "C"));
    emitter.onNext(() -> task(0, "D"));
    emitter.onComplete();
})
.concatMap(call ->
    Observable.fromCallable(call)
       .subscribeOn(Schedulers.computation())
       .timeout(1, TimeUnit.SECONDS, Observable.just("timeout")) 
);

source
      .blockingSubscribe(s -> System.out.println("RECEIVED: " + s));

如何防止超时（...）取消流发射？

1 个答案: