Question

在＆＃34; table1＆＃34;中更改值时遇到问题来自＆＃34; table2＆＃34;使用INSERT INTO SELECT声明。将table2复制到table1中。

让我解释一下......

你在下面的table2的SELECT语句中看到 AND group_name = 'djsfshj' ...我需要将该值（djsfshj）放入＆＃34; table1＆＃34;但是当我运行我的代码时，table1并没有添加任何东西。它有点忽略它，我没有错误。如果我删除AND group_name = 'djsfshj'我的代码有效，但group_name将为空。

我在想我怎样才能让它发挥作用。知道为什么会这样吗？任何帮助表示赞赏！

代码：

foreach ($_GET["users_slideshows"] as $users_pick) {

$sql = "INSERT INTO table1 (username, volume, name, image, content, cssanimate, group_name) 

SELECT '".$user_data['data']['username']."', volume, name, image, content, cssanimate, group_name
        FROM table2 WHERE volume IN ('".$users_pick."') AND group_name = 'djsfshj' ";

        if ($conn->query($sql) === TRUE) {
            echo "";
        } else {
            echo "Error: " . $sql . "<br>" . $conn->error;
        }

}

Answer 1

尝试使用PHP's join将变量$_GET["users_slideshows"]的内容设为逗号分隔值

$users_pick = join(',',$_GET["users_slideshows"]);

Answer 2

我发现查询中的引文不准确，您可以尝试：

$sql = "INSERT INTO table1 (username, volume, name, image, content, cssanimate, group_name) ";
foreach ($_GET["users_slideshows"] as $users_pick) {
$sql .= "SELECT ".$user_data['data']['username'].", volume, name, image, content, cssanimate, group_name
        FROM table2 WHERE volume IN ('".$users_pick."') AND group_name = 'djsfshj' ";
}


        if ($conn->query($sql) === TRUE) {
            echo "";
        } else {
            echo "Error: " . $sql . "<br>" . $conn->error;
        }

用多个where语句查询？

2 个答案: