Question

我很难从下面提到的列表中创建嵌套字典：

student = ['Mike','Frank']
Type = ['Midterm1','Midterm2','Final']
Scores = [[10,20,30],[40,50,60]]

我正在寻找以下字典：

 Scorecard = {'Mike':'Midterm':10,'Midterm2':20,'Final':30},'Frank':   
             {'Midterm':40,'Midterm2':50,'Final':60}}

我能够创建学生和类型组合，但难以在学生级别嵌套类型和值。

输出为

scorecard['Mike']['Midterm'] = 10
         ['Mike']['Midterm2'] = 20

Answer 1

这是一个简洁的单行：

In [4]: dict(zip(student, (dict(zip(Type, score)) for score in Scores)))
Out[4]:
{'Frank': {'Final': 60, 'Midterm1': 40, 'Midterm2': 50},
 'Mike': {'Final': 30, 'Midterm1': 10, 'Midterm2': 20}}

这里的循环更明确一点：

In [5]: scorecard = {}

In [6]: for st, score in zip(student, Scores):
   ...:     scorecard[st] = dict(zip(Type,score))
   ...:
   ...:

In [7]: scorecard
Out[7]:
{'Frank': {'Final': 60, 'Midterm1': 40, 'Midterm2': 50},
 'Mike': {'Final': 30, 'Midterm1': 10, 'Midterm2': 20}}

如何在Python中创建嵌套字典？

1 个答案: