Question

我有这个系列

{“ip”：“192.168.141.1”，“ifsIndex”：“28”，“link”：“1”，“timeStamp”：“19-01-2018 18:12:42”} {“ip”：“192.168.141.1”，“ifsIndex”：“30”，“link”：“1”，“timeStamp”：“19-01-2018 18:12:42”} {“ip”：“192.168.141.1”，“ifsIndex”：“32”，“link”：“1”，“timeStamp”：“19-01-2018 18:12:42”} {“ip”：“192.168.141.1”，“ifsIndex”：“29”，“link”：“1”，“timeStamp”：“19-01-2018 18:12:42”} {“ip”：“192.168.141.1”，“ifsIndex”：“31”，“link”：“1”，“timeStamp”：“19-01-2018 18:12:42”} {“ip”：“192.168.141.1”，“ifsIndex”：“28”，“link”：“1”，“timeStamp”：“19-01-2018 18:14:16”} {“ip”：“192.168.141.1”，“ifsIndex”：“29”，“link”：“1”，“timeStamp”：“19-01-2018 18:16:33”} {“ip”：“192.168.141.1”，“ifsIndex”：“32”，“link”：“1”，“timeStamp”：“19-01-2018 18:14:09”} {“ip”：“192.168.141.1”，“ifsIndex”：“28”，“link”：“1”，“timeStamp”：“19-01-2018 18:16:33”} {“ip”：“192.168.141.1”，“ifsIndex”：“30”，“link”：“1”，“timeStamp”：“19-01-2018 18:14:16”} {“ip”：“192.168.141.1”，“ifsIndex”：“31”，“link”：“1”，“timeStamp”：“19-01-2018 18:16:33”} {“ip”：“192.168.141.1”，“ifsIndex”：“29”，“link”：“1”，“timeStamp”：“19-01-2018 18:14:16”} {“ip”：“192.168.141.1”，“ifsIndex”：“30”，“link”：“1”，“timeStamp”：“19-01-2018 18:16:33”} {“ip”：“192.168.141.1”，“ifsIndex”：“31”，“link”：“1”，“timeStamp”：“19-01-2018 18:14:16”} {“ip”：“192.168.141.1”，“ifsIndex”：“32”，“link”：“1”，“timeStamp”：“19-01-2018 18:16:33”}

我想将ip地址和ifsIndex组合在一起，并显示link和timeStamp的数组，并在排序的timestamp中显示结果。我试过这个

db.events.aggregate([{$group:{_id:{"ifIndex":"$ifsIndex","ip":"$ip"},status:{$push:"$link"},timeStamp:{$push:"$timeStamp"}}},{$sort:{"timeStamp":1}}])

我得到的结果不是我想要的。某些值未按timeStamp

排序

{ "_id" : { "ifIndex" : "31", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:16:33", "19-01-2018 18:14:16" ] }
{ "_id" : { "ifIndex" : "29", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:16:33", "19-01-2018 18:14:16" ] }
{ "_id" : { "ifIndex" : "32", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:14:09", "19-01-2018 18:16:33" ] }
{ "_id" : { "ifIndex" : "30", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:14:16", "19-01-2018 18:16:33" ] }
{ "_id" : { "ifIndex" : "28", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:14:16", "19-01-2018 18:16:33" ] }

ifIndex 31和29的timeStamp未排序，其他排序。我在这做错了什么？

Answer 1

$sort时间戳然后执行$group以获取$push已排序

db.events.aggregate(
    [   
        {$sort:{"timeStamp":1}},
        {$group:{_id:{"ifIndex":"$ifsIndex","ip":"$ip"},status:{$push:"$link"},timeStamp:{$push:"$timeStamp"}}}

    ]
)

结果

> db.events.aggregate( [ {$sort:{"timeStamp":1}}, {$group:{_id:{"ifIndex":"$ifsIndex","ip":"$ip"},status:{$push:"$link"},timeStamp:{$push:"$timeStamp"}}}  ])
{ "_id" : { "ifIndex" : "31", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:14:16", "19-01-2018 18:16:33" ] }
{ "_id" : { "ifIndex" : "28", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:14:16", "19-01-2018 18:16:33" ] }
{ "_id" : { "ifIndex" : "29", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:14:16", "19-01-2018 18:16:33" ] }
{ "_id" : { "ifIndex" : "30", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:14:16", "19-01-2018 18:16:33" ] }
{ "_id" : { "ifIndex" : "32", "ip" : "192.168.141.1" }, "status" : [ "1", "1", "1" ], "timeStamp" : [ "19-01-2018 18:12:42", "19-01-2018 18:14:09", "19-01-2018 18:16:33" ] }
>

有一种方法可以在更新操作中对数组元素进行排序，但不能在聚合doc

中进行排序

根据时间戳排序mongodb聚合

1 个答案: