Question

我有下表：

id   income created_at
-----------------------
966  300    1516182896
965  -1050  1516188513
964  2000   1516444061
963  600    1513267843

我正在运行以下查询以获取每日收入总和（过去10天）：

SELECT sum(income) AS income, `created_at`
FROM `incomes`
WHERE `created_at` BETWEEN (UNIX_TIMESTAMP(NOW() - INTERVAL 10 DAY))
  AND UNIX_TIMESTAMP(NOW())
GROUP BY DATE(FROM_UNIXTIME("created_at"))

我得到：

income  created_at
-------------------
1850    1516182896

它给出了总和，无论日期与最后一个created_at有关。

我在那里错过了什么？

Answer 1

您正在转换字符串created_at - 删除引号或使用mysql转义字符（反引号）。注意创建时仍然是不确定的你可能应该选择DATE（FROM_UNIXTIME（created_at））

Answer 2

SELECT sum(income) AS income, DAYOFYEAR(FROM_UNIXTIME(created_at)) as doy
FROM `incomes`
WHERE `created_at` BETWEEN (UNIX_TIMESTAMP(NOW() - INTERVAL 10 DAY))
  AND UNIX_TIMESTAMP(NOW())
GROUP BY doy;

您通过varchar "created_at"而非列created_at进行分组，从而产生了错误。

Answer 3

你应该添加日期来选择：

SELECT sum(income) AS income, `created_at`, DATE(FROM_UNIXTIME(`created_at`)) as dd
FROM `incomes`
WHERE `created_at` BETWEEN (UNIX_TIMESTAMP(NOW() - INTERVAL 10 DAY))
  AND UNIX_TIMESTAMP(NOW())
GROUP BY dd

mysql查询组按天计算在时间戳上

3 个答案: