项目没有显示在组合框wpf中

Question

我有ComboBox

<ComboBox Grid.Column="1" Grid.Row="1" Margin="3" Name="cmbPlayer1" IsEditable="true"></ComboBox>

我用数据库中的数据初始化我的Combobox。我有程序初始化这个，然后我调用这个程序。

Public Sub InitComboxesPlayers(cmbPlayer As ComboBox)
    Using myDataReader As SqlDataReader = GetSqlFunctions.GetExecutedDataReaderFromSql(
         "SELECT PLAYER_ID,        " &
         "       PLAYER_NICKNAME,  " &
         "       PLAYER_FIRSTNAME, " &
         "       PLAYER_LASTNAME   " &
         "  FROM PLAYERS ", myConnection)

        While myDataReader.Read
            Dim myNewPlayer As New Players
            With myNewPlayer
                .Player_ID = CInt(myDataReader("PLAYER_ID"))
                .Nickname = myDataReader("PLAYER_NICKNAME").ToString.Trim
                .Firstname = myDataReader("PLAYER_FIRSTNAME").ToString.Trim
                .Lastname = myDataReader("PLAYER_LASTNAME").ToString.Trim
            End With
            lstOfPlayers.Add(myNewPlayer)
        End While
    End Using

    cmbPlayer.ItemsSource = lstOfPlayers
    cmbPlayer.DataContext = lstOfPlayers
    cmbPlayer.DisplayMemberPath = "PLAYER_NICKNAME"
    cmbPlayer.SelectedValuePath = "PLAYER_ID"

End Sub

Public Sub New()

    ' This call is required by the designer.
    InitializeComponent()

    ' Add any initialization after the InitializeComponent() call.
    InitComboxesPlayers(cmbPlayer1)

End Sub

因此，我的值不会显示在组合框中。但你可以在图片上看到值在Combobox中，因为它不是空的。怎么了？

Answer 1

试试这个......您需要 分配您的类 中的属性名称，而不是来自您的SQL的列名......

 cmbPlayer.DisplayMemberPath = "Nickname"
 cmbPlayer.SelectedValuePath = "Player_ID"

Answer 2

两种方法： -

1）更新代码以使用属性而不是DataBase列名： -

cmbPlayer.DisplayMemberPath = "Nickname "

2）您可以为组合框创建项目模板，因此您无需在代码中设置DisplayMemberPath。

    <ComboBox Grid.Column="1" Grid.Row="1" Margin="3" Name="cmbPlayer1" IsEditable="true">
    <ComboBox.ItemTemplate>
        <DataTemplate>
            <TextBlock Text={Binding Nickname}
        </DataTemplate>
    </ComboBox.ItemTemplate>
    </ComboBox>