如何获取char数组的长度而不多次显示它

Question

如何将它们分开，以便根据char的长度不显示多次？除了for循环之外，我还可以使用其他方法来实现我需要的输出。这是代码：

for(i=0;i <= s.length; i++){
    int fc = s.length;

    if(fc == 1){
        System.out.println("String accepted under rule a*");
    }
    if(fc == 2 || fc == 4){
        System.out.println("String accepted under rule a*b+");
    }
    if(fc >= 5 ){
        System.out.println("String accepted under rule abb");
    }
}

输出：

我的意思是我如何只使用一个“在规则a*b+下接受的字符串”而不是根据数组的长度显示它。

Answer 1

您可以删除循环并只使用if-else语句

int fc = s.length;

if(fc == 1) {
   System.out.println("String accepted under rule a*");
}
else
if(fc == 2 || fc == 4) {
   System.out.println("String accepted under rule a*b+");
}
else
if(fc >= 5 ) {
   System.out.println("String accepted under rule abb");
}

或

在每个break

中添加if statement语句

for(i=0;i <= s.length; i++) {

     int fc = s.length;

     //make sure that fc is not equal to 0 to avoid infinite loop
     if(fc == 0) { 
        break;
     }

     if(fc == 1) {
         System.out.println("String accepted under rule a*");
         break;
     }
     if(fc == 2 || fc == 4) {
         System.out.println("String accepted under rule a*b+");
         break;
     }
     if(fc >= 5 ) {
         System.out.println("String accepted under rule abb");
         break;
     }
}

Answer 2

如果代码中的任何内容在代码的每次迭代中都没有变化，为什么还需要循环？

   int fc = s.length;


   if(fc == 1){
       System.out.println("String accepted under rule a*");
   }
   if(fc == 2 || fc == 4){
       System.out.println("String accepted under rule a*b+");
   }
   if(fc >= 5 ){
        System.out.println("String accepted under rule abb");
   }

或添加break语句以终止每个if

内的循环

Answer 3

int fc = s.length;
if(fc == 1){
    System.out.println("String accepted under rule a*");
}
if(fc == 2 || fc == 4){
    System.out.println("String accepted under rule a*b+");
}
if(fc >= 5 ){
    System.out.println("String accepted under rule abb");
}