FragmentPagerAdapter没有调用getItem()方法

时间:2018-01-23 05:12:57

标签: java android android-fragments android-viewpager android-fragmentactivity

我正在创建具有Viewpager和自定义片段类的自定义视图。问题是我没有调用getItem(int position)。即使这是在另一个pagerview。请告诉我我的代码有什么问题。谢谢!!

 private void initView(Context context) {
                this.context = context;
                LayoutInflater inflater = LayoutInflater.from(context);
                rootView = inflater.inflate(R.layout.internal_training_view, this, true);
                Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
                ((HFTrainingActivityDashBord)context).setSupportActionBar(toolbar);
                ((HFTrainingActivityDashBord)context).setSupportActionBar(toolbar);
                mSectionsPagerAdapterInternal = new SectionsPagerAdapter(((HFTrainingActivityDashBord)context).getSupportFragmentManager());
                mViewPagerInternal = (CustomViewPager) findViewById(R.id.pager_hf_training);
                mViewPagerInternal.setOffscreenPageLimit(3);
                mViewPagerInternal.setAdapter(mSectionsPagerAdapterInternal);
                TabLayout tabs_hf = (TabLayout) findViewById(R.id.tabs_hf);
                tabs_hf.setupWithViewPager(mViewPagerInternal);

              }        
        public class SectionsPagerAdapter extends FragmentPagerAdapter {

                public SectionsPagerAdapter(FragmentManager fm) {
                    super(fm);
                }

                @Override
                public Fragment getItem(int position) {                       

                    return new IternalTrainingDashBoardFragment(position,context);
                }

                @Override
                public int getCount() {
                    // Show 4 total pages.
                    return 4;
                }

                @Override
                public CharSequence getPageTitle(int position) {
                    switch (position) {
                        case 0:
                            return "All";
                        case 1:
                            return "InProgress";
                        case 2:
                            return "Overdue";
                        case 3:
                            return "Not Started";


                    }
                    return null;
                }

            }

1 个答案:

答案 0 :(得分:2)

我认为问题在于如何在fragments方法中返回getItem()。使用片段中的静态newInstance()方法创建片段。不确定是否要使用其构造函数调用片段,而不是newInstance工厂方法这是一个示例。

@Override
public Fragment getItem(int position) {
    switch (position) {
        case 0:
            //Note I am using the Fragments static newInstance method(). You arent supposed to call a fragment using new
            return DetailInfoFragment.newInstance(someEntity);
        case 1:
            return DetailContentFragment.newInstance(someEntity);
        case 2:
            return DetailExtraFragment.newInstance(someEntity);
        default:
            return DetailInfoFragment.newInstance(someEntity);
    }
}

以下是newInstance

中的示例DetailInfoFragment
public static DetailInfoFragment newInstance(SomeEntity someEntity) 
{
    DetailInfoFragment fragment = new DetailInfoFragment();
    Bundle args = new Bundle();
    args.putParcelable(ARG_PARAM1, someEntity);
    fragment.setArguments(args);
    return fragment;
}
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