Question

我正在尝试从我的数据库中获取数据，但是当我访问MYWEBPAGE.com/service.php?id=2时（是的，有一篇带有该ID的文章），那么它只是写道： [true]，而不是将对象显示为json。

这是我的代码：

＆＃13;

<?php
 

include('includingThis.php');

$idFromUrl = addslashes($_GET[id]);

$resultArray = array();
$tempArray = array();
 
if ($stmtTitle = $con->prepare("SELECT * FROM artikler WHERE id=?")) {
	
	
				
				/* bind parameters for markers */
    			$stmtTitle->bind_param("i", $idFromUrl);
				
				$stmtTitle->execute();
					
				// Loop through each row in the result set
				while($row = $stmtTitle->fetch()) {
						
		// Add each row into our results array
		$tempArray = $row;
	    array_push($resultArray, $tempArray);
	}
 
	// Finally, encode the array to JSON and output the results
	echo json_encode($resultArray);
}
 
// Close connections
mysqli_close($con);
?>

＆＃13;

Answer 1

您遇到的问题是使用fetch。它不返回一行，它返回一个布尔值。如果您希望从准备好的语句中获取一行*字段（使用mysqli），您可以采用以下两种方式之一。

1）如果您有mysqlnd可用：

您首先使用get_result，然后使用fetch_assoc：

<?php
include('includingThis.php');
$resultArray = array();
if ($stmtTitle = $con->prepare("SELECT * FROM artikler WHERE id=?")) {
    $stmtTitle->bind_param("i", $_GET['id']);// just put your GET var here
    $stmtTitle->execute();
    $stmtTitle_result = $stmtTitle->get_result();// get the result object
    while($row = $stmtTitle_result->fetch_assoc()) {
        $resultArray[] = $row;// add each row into resultArray directly
    }
    echo json_encode($resultArray);
}
?>

2）如果您没有mysqlnd可用：

您使用bind_result但必须知道您需要的每个字段:(将字段名称更改为您的字段名称，而不是field和field2的示例

<?php
include('includingThis.php');
$resultArray = array();
if ($stmtTitle = $con->prepare("SELECT field1,field2 FROM artikler WHERE id=?")) {
    $stmtTitle->bind_param("i", $_GET['id']);// just put your GET var here
    $stmtTitle->execute();
    $stmtTitle->bind_result($field1,$field2);// bind to each field
    while($stmtTitle->fetch()) {
        $resultArray[] = array('field1'=>$field1,'field2'=>$field2);// add each field
    }
    echo json_encode($resultArray);
}
?>

顺便说一句，使用PDO库会更容易（更干净）。

Answer 2

您的服务器上可能没有安装mysql本机驱动程序以使用get_result（），请尝试使用bind_result（）

<?php


include('includingThis.php');
$resultArray = array();
if ($stmtTitle = $con->prepare("SELECT value1,value2 FROM artikler WHERE id=?")) {
    $stmtTitle->bind_param("i", $_GET['id']);// just put your GET var here
    $stmtTitle->execute();
    $stmtTitle->store_result();
$stmtTitle->bind_result($value1,$value2);

    while($stmtTitle_result->fetch()) {
   $resultArray->val1=$value1;
  $resultArray->val12=$value2;


    }
    echo json_encode($resultArray);
}
?>

从数据库中获取，如JSON

2 个答案: