数据插入xml文件后的C#成功消息

时间:2018-01-30 20:02:54

标签: c# winforms

我试图尝试捕获错误并显示成功消息,如果在xml文件中保存为true但我不知道如何绕过它。谁能帮忙。以下是我的代码:

dataentry.cs

 try
        {
            teacher.Save();
            if ()
            {
                MessageBox.Show("Teacher saved!!!","Success");
            }
        }
        catch(Exception errorSave)
        {
            MessageBox.Show("Problem with savin file", "Error" + errorSave.Message);
        }

person.cs

protected void Save(string typeName)
    {
        string targetDirectory = CreateTargetDirectory(typeName);

        //2. Generate the path to the target file
        string filePath = targetDirectory + ID + ".xml";

        //3. Serialise the object
        //4. Save the object to the target file
        XmlSerializer xmlSerializer = new XmlSerializer(this.GetType());

        using (FileStream dataStream = new FileStream(filePath, FileMode.Create))
        {
            xmlSerializer.Serialize(dataStream, this);
            dataStream.Close();
        }

    }

teacher.cs

 public class Teacher:Person
{

    public void Save()
    {
        Save("teacher");
    }

    public static List<Teacher> Load()
    {
        return Load<Teacher>("teacher");
    }

    public decimal RatePerHour { get; set; }
    public List<string> ClassNames { get; set; }
    public string Subject { get; set; }
    public string ClassName { get; set; }
}

2 个答案:

答案 0 :(得分:3)

如果teacher.Save();抛出异常,则会跳过try块中的后续行。

如果teacher.Save();没有抛出异常,您可以认为保存成功。

这两件事意味着您不需要在成功消息框周围添加if语句。

try
{
    teacher.Save();
    MessageBox.Show("Teacher saved","Success");
}
catch(Exception saveError)
{
    MessageBox.Show("Problem saving file", "Error" + saveError.Message);
}

答案 1 :(得分:1)

这个怎么样?

bool isSuccess = false;
string resultMessage = "File save {0}. {1}";

try
{
    teacher.Save();

    isSuccess = true;
    resultMessage = string.Format(resultMessage, "succeeded", string.Empty);
}
catch(Exception errorSave)
{
    //Log error here

    //Set response message
    resultMessage = string.Format(resultMessage, "failed", errorSave.Message);
}
finally
{
    MessageBox.Show (resultMessage, isSuccess? "Success" : "Error");
}
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